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creativ13 [48]
3 years ago
9

2. Find the time taken by the bus to reach the stop. need only group B, 2 answer

Physics
1 answer:
Molodets [167]3 years ago
3 0

Answer:

t = 2 seconds

Explanation:

In 2nd question, the question is given the attached figure.

Initial speed of the bus, u = 0

Acceleration of the bus, a = 8 m/s²

Final speed, v = 16 m/s

We need to find the time taken by the car to reach the stop. Acceleration of an object is given by :

a=\dfrac{v-u}{t}

t is time taken

t=\dfrac{v-u}{a}\\\\t=\dfrac{16-0}{8}\\\\t=2\ s

The bus will take 2 seconds to reach the stop.

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A dolphin in an aquatic show jumps straight up out of the water at a velocity of 13.0 m/s.
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Answer:

a) Knowns, initial speed v_{i}=13.0 m/s, final speed v_{f}=0 m/s and gravity due it is a constant g=9.8m/s^{2}

b) The maximum high reached by the dolphin is y_{max}=8.62 m

c) Total time is t=2.65s

Explanation:

a) First of all the initial speed is given at the start of the problem, gravity is constant and final speed is known any object thrown straight up reaches its max high at 0m/s speed.

b) Second, now that we know final speed we use v_{f} =v_{i}-gt, as we clear for t=\frac{v_{i}-v_{f} }{g}=\frac{20.0m/s}{9.8m/s^{2} }=1.32 s.

Then we use y=v_{i}t-\frac{1}{2} gt^{2}=(20.0m/s)(1.32s)-\frac{1}{2} (9.8m/s^{2} ) (1.32s)^{2}  =8.62m

c)Third, finally we can use y=v_{i}t-\frac{1}{2} gt^{2}, as we know y=0m when the dolphin fall into the water again and v_{i} =13.0m/s, then we have 0=(13m/s)t-\frac{1}{2} (9.8m/s^{2}  )t^{2} is a quadratic form 0=t(13.0-4.9t) so we have t_{i}=0s and t_{f}=\frac{13}{4.90}  =2.65s

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When do vernal equinoxes usually occur? autumnal?
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How much energy is needed to change 100 g of 0o C ice to 0o C water? The latent heat of fusion for water L=335,000 J/kg. Hint: T
pychu [463]

Answer:

33.5 kJ

Explanation:

here there is no difference is made in the temperature. Only thing happens here is the conversion of the ice in to water of 0 degree. The heat energy taken from the outside is spent for this conversion.

we have ice 100g =0.1 kg

Appplying Q=mL

                  Q= 0.1 kg * 335 000 J kg^{-1}

                   Q = 33 500 J

                   Q = 33.5 kJ

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3 years ago
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an
nalin [4]

Answer:

The maximum volume is 1417.87 inch^3

Explanation:

<u>Optimization Using Derivatives</u>

We have a 24x30 inch piece of metal and we need to make a rectangular box by cutting a square from each corner of the piece and bending up the sides. The width of the piece is 24 inches and its length is 30 inches

When we cut a square of each corner of side x, the base of the box (after bending up the sides) will be (24-2x) and (30-2x), width and length respectively. The volume of the box is

V=(24-2x)(30-2x)x

Operating

V=4x^3-108x^2+720x

To find the maximum value of V, we compute the first derivative and equate it to zero

V'=12x^2-216x+720=0

Simplifying by 12

x^2-18x+60=0

Completing squares

x^2-18x+81-81+60=0

(x-9)^2=21

We have two values for x

x=9+\sqrt{21}=13.58\ inch

x=9-\sqrt{21}=4.42\ inch

The first value is not feasible because it will produce a negative width (24-2(13.58))=-6.16

We'll keep only the solution

x=4.42\ inch

The width is

w=(24-2(4.42))=15.16\ inch

The length is

l=(30-2(4.42))=21.16\ inch

And the height

x=4.42\ inch

The maximum volume is

V=(15.16)(21.16)(4.42)=1417.87\ inch^3

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