Answer:
Lighting Bunsen Burner:
Explanation:
Close needle valve and collar. Open gas valve fully. Open needle valve 1/2 turn. Use the spark/lighter to light the flame.
I would say <span>4. 40. g at 15°C because kinetic energy is related to temperature and not mass, so the lower temp would give you lower KE</span>
A cubic centimeter is equal in volume to one milliliter
The new volume is mathematically given as
V2= 16.12 L
<h3>
What is the new volume?</h3>
Question Parameters:
A sample of gas has an initial volume of 20 L
and an initial pressure of 2.5 atm.
If the pressure changes to 3.1 atm
Generally, the equation for Pressure is mathematically given as
P1V1 = P2 V2
2.5 * 20 = 3.1 * V2
V2 = 50/3.1
V2= 16.12 L
For more information on volume
brainly.com/question/1578538
Explanation:
The chemical equation is as follows.
And, the given enthalpy is as follows.
; 
= 102.5 kJ
Cl-Cl = 243 kJ/mol, O=O = 498 kJ/mol
Since, the bond enthalpy of Cl-Cl is not given so at first, we will calculate the value of Cl-Cl as follows.
102.5 = ![[(\frac{1}{2})x + 498] - [(2)(243)]](https://tex.z-dn.net/?f=%5B%28%5Cfrac%7B1%7D%7B2%7D%29x%20%2B%20498%5D%20-%20%5B%282%29%28243%29%5D)
102.5 = 
102.5 - 12 = 
x = 181 kJ
Now, total bond enthalpy of per mole of ClO is calculated as follows.
x = ![[(\frac{1}{2})181 + (\frac{1}{2})498] - 243](https://tex.z-dn.net/?f=%5B%28%5Cfrac%7B1%7D%7B2%7D%29181%20%2B%20%28%5Cfrac%7B1%7D%7B2%7D%29498%5D%20-%20243)
= 339.5 - 243
= 96.5 kJ
Thus, we can conclude that the value for the enthalpy of formation per mole of ClO(g) is 96.5 kJ.
