Answer:
43.75 ml
Explanation:
Given that the equation of the reaction is;
2HNO3(aq) + Ca(OH)2(aq) ---> Ca(NO3)2(aq) + 2 H20(l)
Concentration of acid CA= 0.05 M
Concentration of base CB = 0.02 M
Volume of acid VA = 35.00ml
Volume of base VB= ???
Number of moles of acid NA= 2
Number of moles of base NB=1
From
CAVA/CBVB= NA/NB
Making VB the subject of the formula;
VB= CAVANB/CBNA
VB= 0.05 × 35 × 1/ 0.02 × 2
VB=1.75 /0.04
VB= 43.75 ml
Is This it? I’m sorry if it wasn’t
<u>Answer:</u> Step 2 in the given mechanism is the rate determining step
<u>Explanation:</u>
In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.
The intermediate reaction of the mechanism follows:
<u>Step 1:</u> 
<u>Step 2:</u> 
As, step 2 is the slow step. It is the rate determining step
Rate law for the reaction follows:
![\text{Rate}=k[O_3][O]](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BO_3%5D%5BO%5D)
Hence, step 2 in the given mechanism is the rate determining step
Answer:
Approximately 53.3 %.
Explanation:
Molar mass of C2H4O2
= 2 * 12.011 + 4 * 1.008 + 2 * 15.999
= 60.052
% oxygen = (31.998* 100) / 60.052 = 53.28 %