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3 years ago

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Help plz! Use the slope formula to find the missing coordinate. m = 2, A(_, 0), B(5, 10)

1 answer:

kakasveta [241]3 years ago

3 0

X=0

you use the slope formula (y2-y1) divided by (x2-x1) to get (10-0)=(5-x)

x has to be 0.

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I'm new to this and I dont really understand this

agasfer [191]

Answer:

So starting off with 1a f(4)

We simply substitute x with 4 for the function

f(4)=2(4)-5

f(4)=8-5

f(4)=3

Next 1b, here it's a little different since you have to multiply the functions I think ( please correct me if I'm wrong).

gf(4), basically means functions g and f are being multiplied and their variables are being substituted with 4.

g(4)=4^2+3

g(4)=16+3

g(4)=19

and we also know from before that f(4)=3, so we'll do 19 times 3 which is 57

For the next two, I may be wrong, but I'm still going to try:

anything to the power of a negative is a fraction so for f^-1(x)=2x-5 we'll have 1/f(x)=x/2+5/2

And then for g^-1, we'll have 1/g(x)= $\sqrt{x-3} \sqrt{x-3}$

Hope I helped :)

5 0

2 years ago

Can someone help me with this please? I will mark you brainliest

lina2011 [118]

Answer:

On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.vvOn the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.vcOn the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.

Step-by-step explanation:

6 0

3 years ago

Can someone pls help me? :)

erastova [34]

Step-by-step explanation:

1 t=16/21

2.m=2

3.n=13/7

4.a=2

5.x=6/17

6.x=15

7.s=21/4

8. t=7/3

9. s=1

10. s=6/61

11. x=1/3

12. r=27/16

13. c=−1

14.m=9/5n

15. j=−117/58

8 0

3 years ago

A car travels 58.8 kilometers in 2.6 hours. What is the car's average speed?

NISA [10]

Answer:

22.6 km/hr

Step-by-step explanation:

58.8/2.6=22.6

7 0

3 years ago

Read 2 more answers

Area of a trapezium is 31.5cm. If the parallel sides are of lengths 7.3cm and 5.3cm. Calculate the perpendicular distance betwee

Anna11 [10]

Answer:

5cm

Step-by-step explanation:

Given area of trapezium = 31.5 sq. cm

Length of parallel sides = 7.3cm and 5.3cm

Formula to calculate area of trapezium is

1/2*(sum of parallel sides)*perpendicular distance between parallel sides

sum of parallel sides = (7.3 + 5.3) = 12.6cm

substituting value of area given and sum of parallel sides we have

31.5 = 1/2* 12.6 * perpendicular distance between parallel sides

(31.5 * 2)/12.6 = perpendicular distance between parallel sides

perpendicular distance between parallel sides = 63/12.6 = 5

Therefore perpendicular distance between parallel sides for given trapezium is 5cm.

5 0

3 years ago