Question

In Part A, we saw that the theoretical yield of aluminum oxide is 1.60 mol . Calculate the percent yield if the actual yield of aluminum oxide is 1.22 mol .

Answer 1

Taking into account definition of percent yield, the percent yield for the reaction is 76.25%.

Percent yield

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

$percent yield=\frac{actual yield}{theorical yield}x100$

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

Percent yield in this case

In this case, you know:

• actual yield= 1.22 mol
• theorical yield= 1.60 mol

Replacing in the definition of percent yields:

$percent yield=\frac{1.22 mol}{1.60 mol}x100$

Solving:

percent yield= 76.25%

Finally, the percent yield for the reaction is 76.25%.

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