Holes in volcanic rocks illustrates a low pressure and rapid cooling environment(surface of the earth).
Explanation:
Holes in rocks are usually found in a special type of volcanic rock called pumice. The holes signifies a melt that has a lot of dissolved gases in them and they solidify rapid under surface temperature.
- Pockets of holes found in some rocks are as a result of trapped gases in cavities of a solidifying magma.
- The magma must erupt explosively so that the gases will not have enough time to escape.
- During an extrusive magma activity, the low pressure allows for dissolved gases to collects in cavities and magma cools rapidly around them due to the low surface temperature.
- The cavities left behind when the gases escape is the hole formed in volcanic rocks.
Learn more:
volcanic eruptions brainly.com/question/1820994
lava volcanic dome brainly.com/question/12426233
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I believe it would be c: 3 because you can have the numbers -1,0,1.
Answer:
Calcium
Explanation:
"Calcium is a mineral that is necessary for life. In addition to building bones and keeping them healthy, calcium enables our blood to clot, our muscles to contract, and our heart to beat. About 99% of the calcium in our bodies is in our bones and teeth.
"
Answer:
<u>225.6 kJ</u>, <em>assuming the water is already at 100 °C</em>
Explanation:
The correct answer to this question will depend on the initial temperature of the water to which heat is added to produce steam. Energy is required to raise the water temperature to 100°C. At that point, an energy of vaporization is needed to convert liquid water at 100 °C to water vapor at 100°C. The heat of vaporization for water is 2256.4 kJ/kg. The energy required to bring 100g of water from a lower temperature to 100°C is calculated at 4.186 J/g°C. We don't know the starting temperature, so this step cannot be calculated.
<em><u>Assuming</u></em> that we are already at 100 °C, we can calculate the heat required for vaporization:
(100.0g)(1000.0g/1 kg)(2256.4 kJ/kg) = 225.6 kJ for 100 grams water.
The second volume : V₂= 0.922 L
<h3>
Further explanation
</h3><h3>Given
</h3>
7.03 Liters at 31 C and 111 Torr
Required
The second volume
Solution
T₁ = 31 + 273 = 304 K
P₁ = 111 torr = 0,146 atm
V₁ = 7.03 L
At STP :
P₂ = 1 atm
T₂ = 273 K
Use combine gas law :
P₁V₁/T₁ = P₂V₂/T₂
Input the value :
0.146 x 7.03 / 304 = 1 x V₂/273
V₂= 0.922 L
