Question

What volume of carbon dioxide in liters could be generated at 0.96 atm and 362. K by the combustion of 228.85 grams of oxygen gas excess pentane gas (C5H12)?
C5H12(g) + 8 O2(g) ---> 5 CO2(g) + 6 H2O(g)

(OR C5 H12 ("g") + 8 O2 ("g") right arrow 5 C O2 ("g") + 6 H2 O ("g")




Do not type units with your answer

Answer 1

589L volume of carbon dioxide in litres could be generated at 0.96 atm and 362. K by the combustion of 228.85 grams of oxygen gas excess pentane gas ($C_5H_{12}$)

What is an ideal gas equation?

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

$C_5H_{12}(g) + 8 O_2(g)$ --->$5 CO_2(g) + 6 H_2O(g)$

To find the volume, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this equation,

P = pressure (atm)

V = volume (L)

n = number of moles

R = constant (0.0821 L*atm/mol*K)

T = temperature (K)

To find the volume of water vapour, you need to (1) convert grams C₅H₁₂ to moles C₅H₁₂ (via molar mass), then (2) convert moles C₅H₁₂ to moles H₂O (via mole-to-mole ratio from reaction coefficients), then (3) calculate volume H₂O (via Ideal Gas Law). The final answer should have 3 sig figs.

Molar Mass (C₅H₁₂) =72.151 g/mol

1 C₅H₁₂ (g) + 8 O₂ (g) -----> 5 CO₂ (g) + 6 H₂O (g)

228.85 g C₅H₁₂           1 mole            6 moles H₂O

-----------------------  x  ----------------  x  -----------------------  =  19.03 moles H₂O

                                 72.151 g           1 mole C₅H₁₂

Moles of H₂O=  19.03

P =0.96 atm            

R = 0.0821 L x atm/mol x K

V = ?                          

T = 362 K

n =  19.03 moles

PV = nRT

(0.96  atm)V = ( 19.03 moles)(0.0821 Latm/molK)(362K)

(0.96  atm)V = 565.575406

V = 589L

Hence, 589L volume of carbon dioxide in litres could be generated at 0.96 atm and 362. K by the combustion of 228.85 grams of oxygen gas excess pentane gas ($C_5H_{12}$).

Learn more about the ideal gas here:

brainly.com/question/27691721

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