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Semmy [17]
3 years ago
11

Every afternoon, Bill and Anita go down to the beach to fly their kite. They noticed that the wind always blows towards shore. W

hy is this? PLEASE HELP QUICKLY
The energy of ocean waves pushes air towards shore

Earth's rotation causes air to blow toward land

Ocean air is less dense, so it moves in to replace air over the land

Air over the beach heats up, rises, and is replaced by cool, denser ocean air
Chemistry
1 answer:
EastWind [94]3 years ago
8 0

Answer:

the answer is D

Explanation:

Air over the beach heats up, rises, and is replaced by cool, denser ocean air

The ocean heats up much slower and becomes relatively cooler than the beach making it a high pressure zone. The air moves from the water to the land each morning forming a sea breeze. These pressure zones might equal out later in the day and the winds may diminish. ... A sea breeze blows from the ocean towards the beach.

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What volume of 0.152 M KMnO4 solution would completely react with 20.0 mL of 0.381 M FeSO4 solution according to the following n
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<u>Answer:</u> The volume of permanganate ion (potassium permanganate) is 10.0 mL

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}     .....(1)

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Putting values in equation 1, we get:

0.381M=\frac{\text{Moles of ferrous sulfate}}{0.020L}\\\\\text{Moles of ferrous sulfate}=(0.381mol/L\times 0.020L)=0.00762mol

For the given chemical equation:

5Fe^{2+}+8H^++MnO_4^-\rightarrow 5Fe^{3+}+Mn^{2+}+4H_2O

By Stoichiometry of the reaction:

5 moles of iron (II) ions (ferrous sulfate) reacts with 1 mole of permanganate ion (potassium permanganate)

So, 0.00762 moles of iron (II) ions (ferrous sulfate) will react with = \frac{1}{5}\times 0.00762=0.00152mol of permanganate ion (potassium permanganate)

Now, calculating the volume of permanganate ion (potassium permanganate) by using equation 1, we get:

Molarity of permanganate ion (potassium permanganate) = 0.152 M

Moles of permanganate ion (potassium permanganate) = 0.00152 mol

Putting values in equation 1, we get:

0.152mol/L=\frac{0.00152mol}{\text{Volume of permanganate ion (potassium permanganate)}}\\\\\text{Volume of permanganate ion (potassium permanganate)}=\frac{0.00152mol}{0.152mol/L}=0.01L=10.0mL

Hence, the volume of permanganate ion (potassium permanganate) is 10.0 mL

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