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Marizza181 [45]
3 years ago
14

Explain how physical and chemical properties influence the formation of ocean current and the distribution of marine life.

Chemistry
1 answer:
tia_tia [17]3 years ago
5 0
<h2>Answer:</h2>

The physical and chemical properties of seawater vary according to latitude, depth, nearness to land, and input of fresh water. The physical and chemical properties of seawater have a great effect on organisms, varying especially with the size of the creature. Marine organisms have evolved a wide variety of unique physiological and morphological features that allow them to live in the sea.

<u>H</u><u>o</u><u>p</u><u>e</u><u>f</u><u>u</u><u>l</u><u>l</u><u>y</u><u> </u><u>H</u><u>e</u><u>l</u><u>p</u><u>:</u><u>)</u>

  • <u>#</u><u>C</u><u>a</u><u>r</u><u>r</u><u>y</u><u>O</u><u>n</u><u>L</u><u>e</u><u>a</u><u>r</u><u>n</u><u>i</u><u>n</u><u>g</u>
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Need help with 22 and 24<br>​
choli [55]

Answer:

22:

Formular:

atomic \: mass =  \frac{ \sum(isotopic \: mass \times \%abundance)}{100}  \\

substitute:

atomic \: mass =  \frac{(23.985 \times 78.70) + (24.986 \times 10.13) + (25.983 \times 11.17)}{100}  \\  \\  =  \frac{(1887.620) + (253.108) + (290.230)}{100}  \\  \\  =  \frac{2430.958}{100}  \\  \\ { \boxed{ \boxed{average \: atomic \: mass = 24.3 \: amu}}}

23:

<em>Same</em><em> </em><em>element</em><em> </em><em>is</em><em> </em><em>represented</em><em> </em><em>by</em><em> </em><em>same</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>protons</em><em>.</em><em> </em>

Answer:

6 protons. 6 protons

7 neutrons. 8 neutrons

6 electrons. 6 electrons

Note: <u>Atoms</u><u> </u><u>with</u><u> </u><u>same</u><u> </u><u>proton</u><u> </u><u>number</u><u> </u><u>but</u><u> </u><u>different</u><u> </u><u>mass</u><u> </u><u>number</u><u> </u><u>are</u><u> </u><u>called</u><u> </u><u>isotopes</u>

5 0
3 years ago
Read 2 more answers
When 45 g of an alloy, at 25oC, are dropped into 100.0 g of water, the alloy absorbs 956 J of heat. If the final temperature of
taurus [48]

Answer:

The answer to the question is

The specific heat capacity of the alloy = 1.77 J/(g·°C)

Explanation:

To solve this, we list out the given variables thus

Mass of alloy = 45 g

Initial temperature of the alloy = 25 °C

Final temperature of the alloy = 37 °C

Heat absorbed by the alloy = 956 J

Thus we have

ΔH = m·c·(T₂ - T₁) where  ΔH = heat absorbed by the alloy = 956 J, c = specific heat capacity of the alloy and T₁ = Initial temperature of the alloy = 25 °C , T₂ = Final temperature of the alloy = 37 °C  and m = mass of the alloy = 45 g

∴ 956 J = 45 × C × (37 - 25) = 540 g·°C×c  or

c = 956 J/(540 g·°C) = 1.77 J/(g·°C)

The specific heat capacity of the alloy is 1.77 J/(g·°C)

3 0
3 years ago
Copper was the first metal to be produced from its ore because it is the easiest to smelt, that is, to refine by heating in the
Ganezh [65]

Answer:

57.48%

Explanation:

Calculate the mass of 1 mole of malachite:

MM Cu = 63.55

MM O = 16.00

MM H = 1.01

MM C = 12.01

(Cu_{2}(OH)_{2}CO_{3})

A mole of malachite has:

2 moles of Cu

5 moles of O

2 moles of H

1 mole of C

MW Malachite = 2*MM(CU) + 5*MM(O) + 2*MM(H) + 1 *MM(C)

MW Malachite = 2*63.55 + 5*16.00 + 2*1.01 + 1*12.01

MW Malachite = 221.13

Mass of Cu in a mole of Malachite = 2*MM(CU) = 127.1

Now divide the mass of Cu by the mass of Malachite

%Cu = \frac{127.1}{221.13} =0.5748=57.48%

7 0
3 years ago
How many blizzards are in 13m?
muminat
What do you mean by that? Can you explain further?
7 0
3 years ago
Which is a characteristic of a synthesis reaction
V125BC [204]
Answer:option A
Multiple reactants are used to form one product.
8 0
3 years ago
Read 2 more answers
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