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Rudik [331]
3 years ago
8

How to calculate natural abandunces

Chemistry
1 answer:
Gennadij [26K]3 years ago
5 0

Answer:

Let x equal the percentage abundance of one of the two isotopes. The other isotope must then have an abundance of 100 percent minus x percent, which you express in decimal form as (1 - x). For nitrogen, you can set x equal to the abundance of N14 and (1 - x) as the abundance of N15.

Explanation:

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Softening of water is the application of​
nika2105 [10]

Answer:

Water softening is the process of removing the dissolved calcium and magnesium salts that cause hardness in water

Explanation:

4 0
3 years ago
Not yet answered Marked out of 2.00 What is the concentration of NH4+ in 60.0 mL of a 0.50 M solution of (NH4)3PO4? (To write yo
Softa [21]

Answer : The concentration of NH_4^+ ion is 0.15E^1M

Explanation :

First we have to calculate the moles of (NH_4)_3PO_4.

\text{Moles of }(NH_4)_3PO_4=\text{Concentration of }(NH_4)_3PO_4\times \text{Volume of solution}=0.50M\times 0.06L=0.03mole

The balanced chemical reaction will be:

(NH_4)_3PO_4\rightleftharpoons 3NH_4^++PO_4^{3-}

From the reaction we conclude that,

1 mole of (NH_4)_3PO_4 dissociate to give 3 moles of NH_4^+ ion and 1 mole of PO_4^{3-} ion

So,

0.03 mole of (NH_4)_3PO_4 dissociate to give 3\times 0.03=0.09 moles of NH_4^+ ion and 0.03 mole of PO_4^{3-} ion

Now we have to calculate the concentration of NH_4^+ ion.

\text{Concentration of }NH_4^+=\frac{\text{Moles of }NH_4^+}{\text{Total volume}}

\text{Concentration of }NH_4^+=\frac{0.09mole}{0.06L}=1.5M=0.15E^1M

Therefore, the concentration of NH_4^+ ion is 0.15E^1M

4 0
4 years ago
What is the daughter nucleus produced when Au195 undergoes electron capture?
VashaNatasha [74]

Pt195 having 78 atomic number is the daughter nucleus produced when Au195 undergoes electron capture.

An unstable isotopes can undergoes radioactive decay to form a more stable isotopes . Initial isotopes is called parent nuclide and the resultant isotopes from radioactive decay is called the daughter nuclide There are several radioactive decay like alpha decay , beta decay  , gamma decay , electron capture etc .

In electron capture , the atom have only one less which is daughter isotopes than electron than atomic number of parent isotopes.

learn more about isotopes,

brainly.com/question/11680817

#SPJ4

3 0
2 years ago
Gaseous butane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water . If of water is produced from
krek1111 [17]

The given question is incomplete. The complete question is :

Gaseous butane reacts with gaseous oxygen gas  to produce gaseous carbon dioxide and gaseous water . If 1.31g of water is produced from the reaction of 4.65g of butane and 10.8g of oxygen gas, calculate the percent yield of water. Be sure your answer has the correct number of significant digits in it.

Answer: 28.0 %

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of butane}=\frac{4.65g}{58g/mol}=0.080moles

\text{Moles of oxygen}=\frac{10.8g}{32g/mol}=0.34moles

2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)

According to stoichiometry :

13 moles of O_2 require 2 moles of butane

Thus 0.34 moles of O_2 will require=\frac{2}{13}\times 0.34=0.052moles  of butane

Thus O_2 is the limiting reagent as it limits the formation of product and butane is the excess reagent.

As 13 moles of O_2 give = 10 moles of H_2O

Thus 0.34 moles of O_2 give =\frac{10}{13}\times 0.34=0.26moles  of H_2O

Mass of H_2O=moles\times {\text {Molar mass}}=0.26moles\times 18g/mol=4.68g

{\text {percentage yield}}=\frac{\text {Experimental yield}}{\text {Theoretical yield}}\times 100\%

{\text {percentage yield}}=\frac{1.31g}{4.68g}\times 100\%=28.0\%

The percent yield of water is 28.0 %

6 0
4 years ago
How many significant figures are in 0.00375
Galina-37 [17]

Answer:

There are 3 significant figures

3 0
3 years ago
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