Explanation:
Given that,
Displacement in ice block, ![d=14i-11j](https://tex.z-dn.net/?f=d%3D14i-11j)
Force exerted by water, ![F=158i-179j](https://tex.z-dn.net/?f=F%3D158i-179j)
To find,
Work done by the force during the displacement.
Solve,
We know that the product of force and displacement is called work done. It is also equal to the dot product of force and displacement as :
![W=F.d](https://tex.z-dn.net/?f=W%3DF.d)
![W=(158i-179j).(14i-11j)](https://tex.z-dn.net/?f=W%3D%28158i-179j%29.%2814i-11j%29)
We know that, i.i = j.j = k.k = 1
![W=2212+1969=4181\ J](https://tex.z-dn.net/?f=W%3D2212%2B1969%3D4181%5C%20J)
So, the work done by the force on the block during the displacement is 4181 Joules.
Given:
m(mass of Alex)=100Kg
u(initial velocity)=9 m/s
t(time of impact)=0.2 s
v(final velocity)=0.
Now we know that
v=u+at
We know that v is the final velocity.
u is the initial velocity
a is the acceleration
t is the time of impact
Now substituting these values we get
0=9+ax0.2
-0.2a=9
a=-45m/s^2
Thus the acceleration acting on the body is -45m/s^2
Also we know that
F=mxa
Where F is the force acting on the object.
m is the mass of the object.
a acceleration acting on the object.
F=-100x45
F=-4500 N
Thus the force of impact is -4500N
Answer:
0.833
Explanation:
Power = energy / time
Power = force × distance / time
Power = force × velocity
P = (850 kg) (9.8 m/s²) (1.00 m/s)
P = 8330 W
P = 8.33 kW
The efficiency of the motor is therefore:
e = 8.33 kW / 10.0 kW
e = 0.833
Answer:
the greatest number of protons is astatine (At)
As the displacement of the maxima is calculated with the equation
(displacement)y=(m<span>λD)/slit separation (d)
halving the split separation doubles the displacement</span>