Choices are 10.7<br> 16.9<br> 15.2<br> 17.5

calculate the resistance of 50m length of wire of cross sectional area 0.01 square mm and of resistivity 5*10 to the power minus

Pachacha [2.7K]

$Resistance R = resistivity * length / area

R = 5 10^{-8} * 50 m / 0.01 * 10^{-3} * 10^{-3}

R = 250 Ohms
$

8 0

3 years ago

Q 19.23: A proton is initially moving at 3.0 x 105 m/s. It moves 3.5 m in the direction of a uniform electric field of magnitude

DENIUS [597]

Answer:

The kinetic energy of the proton at the end of the motion is 1.425 x 10⁻¹⁶ J.

Explanation:

Given;

initial velocity of proton, $v_p_i$ = 3 x 10⁵ m/s

distance moved by the proton, d = 3.5 m

electric field strength, E = 120 N/C

The kinetic energy of the proton at the end of the motion is calculated as follows.

Consider work-energy theorem;

W = ΔK.E

$W =K.E_f - K.E_i$

where;

K.Ef is the final kinetic energy

W is work done in moving the proton = F x d = (EQ) x d = EQd

$K.E_f =EQd + \frac{1}{2}m_pv_p_i^2$

$m_p \ is \ mass \ of \ proton = 1.673 \ \times \ 10^{-27} kg \\\\Q \ is \ charge \ of \ proton = 1.6 \times 10^{-19} C$

$K.E_f = 120\times 1.6 \times 10^{-19} \times 3.5 \ + \ \frac{1}{2}(1.673\times 10^{-27})(3\times 10^5)^2 \\\\$

$K.E_f = 6.72\times 10^{-17} \ + \ 7.53 \times 10^{-17} \\\\K.E_f = 14.25 \times 10^{-17} J\\\\K.E_f = 1.425\times 10^{-16} \ J$

Therefore, the kinetic energy of the proton at the end of the motion is 1.425 x 10⁻¹⁶ J.

3 0

3 years ago

When we touch things, how close do atoms get together? Or does anything touch anything else?? Full answer Please 50 - 100 words

kkurt [141]

Well, im pretty sure that when we do touch eachother, the atoms themselves are touching. idk if this is what ur looking for but hope this helps.

3 0

3 years ago

Read 2 more answers

Consider two copper wires with circular cross-sections and equal lengths. one wire has 3 times the diameter of the other. How do

Masteriza [31]

The correct option is (C) The longer wire has 3 times the resistance of the shorter wire.

Resistance is a measure of the opposition to current flow in an electrical circuit.

Why do circuits need resistance?

Using ohms (Ω) as the unit, resistance acts as a gauge to quantify how easily current will flow through a circuit. When resistance falls, current rises, and when resistance rises, current falls. In order to make sure that current flows in circuits at the proper rate, resistors are crucial.

How can resistance be determined in a circuit?

By applying Ohm's Law, you can get the total resistance if you know the total current and voltage through the entire circuit: R = V / I. A parallel circuit, for instance, has a voltage of 9 volts and a combined current of 3 amps. Total resistance (RT) is equal to 9 volts / 3 amps, or 3.

Learn more about the Resistance in circuit with the help of the given link:

brainly.com/question/1851488

#SPJ4

I understand that the question you are looking for is "Consider two copper wires of equal cross-sectional area. One wire has 3 times the length of the other. How do the resistances of these two wires compare?

A) Both wires have the same resistance.

B) The longer wire has 1/3 the resistance of the shorter wire.

C) The longer wire has 3 times the resistance of the shorter wire.

D) The longer wire has 9 times times the resistance of the shorter wire.

E) The longer wire has 27 times times the resistance of the shorter wire."

5 0

2 years ago

Which of the following correctly describes the relative air pressure at the center of a hurricane, with respect to the horizonta

vampirchik [111]

Explanation:

The pressure of hurricane which is high decreases gradually as we move higher . The pressure is maximum at the surface . Hence the relative air pressure is higher at the surface and low at the top . Like wise the pressure is low at the center and keeps on increasing when we move outside . Hence the answer is pressure is high at surface and low aloft.

6 0

3 years ago

Choices are 10.7 16.9 15.2 17.5