The results of a _________ test will determine if there is suitable drainage and the size of the drain field that will be requir
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Answer:
COP = 3.828
W' = 39.18 Kw
Explanation:
From the table A-11 i attached, we can find the entropy for the state 1 at -20°C.
h1 = 238.43 KJ/Kg
s1 = 0.94575 KJ/Kg.K
From table A-12 attached we can do the same for states 3 and 4 but just enthalpy at 800 KPa.
h3 = h4 = hf = 95.47 KJ/Kg
For state 2, we can calculate the enthalpy from table A-13 attached using interpolation at 800 KPa and the condition s2 = s1. We have;
h2 = 275.75 KJ/Kg
The power would be determined from the energy balance in state 1-2 where the mass flow rate will be expressed through the energy balance in state 4-1.
W' = m'(h2 - h1)
W' = Q'_L((h2 - h1)/(h1 - h4))
Where Q'_L = 150 kW
Plugging in the relevant values, we have;
W' = 150((275.75 - 238.43)/(238.43 - 95.47))
W' = 39.18 Kw
Formula foe COP is;
COP = Q'_L/W'
COP = 150/39.18
COP = 3.828
The new dimensions of the titanium alloy pin will be that the width is 0.0775 mm and the length is 4.9225m.
<h3>What is Poisson's ratio?</h3>The Poisson's ratio is the proportion of a material's change in width per unit width to its change in length per unit length due to strain. In order for a stable, isotropic, linear elastic material to have a positive Young's modulus, shear modulus, and bulk modulus, the Poisson's ratio must be between 1.0 and +0.5. Poisson's ratio values for the majority of materials fall between 0.0 and 0.5.
The formula for the longitudinal strain is:
= Change in length / Initial length
Based on the information, the longitudinal strain will be:
= 105 - 100 / 100
= 0.05
Poisson ratio will be illustrated as the change in the width divided by the longitudinal strain. :
0.31 = ∆w/5 / 0.05
∆w = 0.0775 mm
New side length will be the difference in the changes in the dimensions:
= w - ∆w
= 5 - 0.0775
= 4.9225m
Learn more about Poisson on:
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