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Digiron [165]
3 years ago
9

How may a Professional Engineer provide notice of licensure to clients?

Engineering
1 answer:
azamat3 years ago
4 0

Find full question attached

Answer:

(b) By including a statement that he or she is licensed by the Board for Professional Engineers and Land Surveyors immediately above the signature line in at least 12 point type on all contracts for services

Explanation:

A PE(professional engineer) licensee must show that he is licensed in order to show and ensure public safety as he is qualified for the job he is handling. The California regulations on professional engineers holds that all professional engineers must be licensed by the board of professional engineers and Land surveyors in order to operate legally as an engineer. The engineer may show licensure through the following options:

The engineer might provide statement to each client to show he is licensed which would then be signed by the client

The engineer may choose to post a wall certificate in his work premises to show he is licensed

The engineer may choose to include a statement of license in a letterhead or contract document which must be above the client's signature line and not less than 12 point type

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In c the square root of a number N can be approximated by repeated calculation using the formula NG = 0.5(LG + N/LG) where NG st
DanielleElmas [232]

Answer:

Following are the program to the given question:

#include <stdio.h>//header file

double square_root(double N, double initialGuess)//defining a method square_root that takes two variable in parameters

{

double NG, LG = initialGuess,diff;//defining double variable

while(1)//use loop to calculate square root value

{

NG = 0.5 * (LG + N / LG);//using given formula

diff = NG - LG;//calculating difference

if(diff < 0)//use if to check difference is less than 0

diff = -diff;//decreaing difference

if(diff < 0.005)//use if that check difference is less than 0.005

break;//using break keyword  

else//defining else block

{

LG = NG;//holding value

}

}

return NG;//return value

}

int main()//defining main method

{

double ans, n,initialguess = 1.0;//defining double variable

n = 4;//use n to hold value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

n = 120.5;//use n to hold value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

n = 36.01;//use n to hold value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

n = 0.25;//use n to hold value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

printf("\nEnter a number: ");//print message

scanf("%lf", &n);//input value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

}

Output:

Please find the attachment file.

Explanation:

  • In this code, a method "square_root" is declared that takes two variable "N, initialGuess" in its parameters, inside the method a three double variable is declared.
  • It uses the given formula and uses the diff variable to hold its value and uses two if to check its value is less than 0 and 0.005 and return its calculated value.
  • In the main method, three double variables are declared that use the "n" to hold value and "ans" to call the method that holds its value and print its value.

8 0
3 years ago
Technician A says that weld-through primer can be removed from the immediate weld area to improve weld quality. Technician B say
lisabon 2012 [21]

Answer:

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4 0
3 years ago
Free brainlist because im new and i just want to but you have t friend me first
Amiraneli [1.4K]
Okay sure.









I’ll 1)chords
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4 0
3 years ago
A thin aluminum sheet is placed between two very large parallel plates that are maintained at uniform temperatures T1 = 900 K, T
Maru [420]

The net radiation heat transfer between the two plates per unit surface area of the plates with shield and without shied are respectively; 2282.76 W/m² and 9766.75 W/m²

<h3>How to find the net radiation heat transfer?</h3>

We are given;

Temperature 1; T₁

Temperature 2; T₂

Temperature 3; T₃

Emissivity 1; ε₁ = 0.3

Emissivity 2; ε₂ = 0.7

Emissivity 3; ε₃ = 0.2

The net rate of radiation heat transfer with a thin aluminum shield per unit area of the plates with shield is;

Q'₁₂ = σ(T₁⁴ - T₂⁴)]/[((1/ε₁) + (1/ε₂) - 1) + ((1/ε₃,₁) + (1/ε₃,₂) - 1)]

Q'₁₂ = 5.67 * 10⁻⁸(900⁴ - 300⁴)/[((1/0.3) + (1/0.7) - 1) + ((1/0.15) + (1/0.15) - 1)]

Q'₁₂,shield = 2282.76 W/m²

The net rate of radiation heat transfer with a thin aluminum shield per unit area of the plates with no shield is;

Q'₁₂,no shield = σ(T₁⁴ - T₂⁴)]/((1/ε₁) + (1/ε₂) - 1))

Q'₁₂,no shield = 5.67 * 10⁻⁸(900⁴ - 300⁴)/[(1/0.3) + (1/0.7) - 1)]

Q'₁₂,no shield = 9766.75 W/m²

Then the ratio of radiation heat transfer for the two cases becomes;

Q'₁₂,shield/Q'₁₂,no shield = 2282.76/9766.75 = 0.2337 or 4/17

Read more about Net Radiation Heat Transfer at; brainly.com/question/14148915

#SPJ1

8 0
2 years ago
In your new role at Wayne Industries, you have been given the freedom to propose and develop your own project ideas. You have an
gulaghasi [49]

Answer:

461.65 KJ/Kg

Explanation:

In this question, we are asked to calculate the values of heat transferred in the process.

Please check attachment for complete solution and step by step explanation

5 0
4 years ago
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