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3 years ago

What is the difference Plastic vs elastic deformation.

Engineering

1 answer:

Reika [66]3 years ago

8 0

Answer:

What is the difference Plastic vs elastic deformation

Explanation:

The elastic deformation occurs when a low stress is apply over a metal or metal structure, in this process, the stress' deformation is temporary and it's recover after the stress is removed. In other words, this DOES NOT affects the atoms separation.

The plastic deformation occurs when the stress apply over the metal or metal structure is sufficient to deform the atomic structure making the atoms split, this is a crystal separation on a limited amount of atoms' bonds.

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Calculate the kinetic energy in kJ of an automobile (3,000 lb) travelling at 60 miles per hour.

AlladinOne [14]

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K = 18.26 KJ

Explanation:

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During experiments on laser etching of microchips for IBM, a nuclear engineer places a discshaped sample 5 mm in diameter in a v

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4 years ago

Your company is planning to build a pipeline to transport gasoline from the refinery to a field of storage tanks. The parameters

AleksandrR [38]

Answer:

The model system will need water flowing at a velocity of 2.07 meters per second to guarantee kinematic similarity in the form of equal Reynolds numbers.

Explanation:

The Reynolds number ( $Re_{D}$ ) is a dimensionless criterion use for flow regime of fluids, which is defined as:

$Re_{D} = \frac{\rho \cdot v\cdot D}{\mu}$ (Eq. 1)

Where:

$\rho$ - Density, measured in kilograms per cubic meter.

$\mu$ - Dynamic viscosity, measured in kilograms per meter-second.

$v$ - Average flow velocity, measured in meters per second.

$D$ - Pipe diameter, measured in meters.

We need to find the equivalent velocity of water used in the prototype system. In this case, we assume that $Re_{D,gas} = Re_{D,w}$ . That is:

$\frac{\rho_{w}\cdot v_{w}\cdot D_{w}}{\mu_{w}} = \frac{\rho_{gas}\cdot v_{gas}\cdot D_{gas}}{\mu_{gas}}$ (Eq. 2)

Where subindex $w$ is used for water and $gas$ for gasoline.

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$57500 = 27777.778\cdot v_{w}$

The fluid velocity for the prototype system is:

$v_{w} = 2.07\,\frac{m}{y}$

The model system will need water flowing at a velocity of 2.07 meters per second to guarantee kinematic similarity in the form of equal Reynolds numbers.

3 0

3 years ago

The Hoover Dam (see the Video) backs up the Colorado River and creates Lake Meade, which is approximately 115 miles long and has

Kamila [148]

Answer: 0.518

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Change in volume per day = 37600 * 3600 * 24 = 3.249e+9 cfd

Total rise of water level per day = Change in volume per day/Total lake area

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7 0

3 years ago

For some alloy, the yield stress is 345-MPa (50,000-psi) and the elastic modulus (E) is 103-GPa (15x106 psi). What is the maximu

OverLord2011 [107]

The maximum load that may be applied to a specimen with a cross-sectional area of 130 mm² is; 35535 N

<h3>How to find Elastic Modulus?</h3>

We are told that for an alloy, the yield stress is 345-MPa and the elastic modulus (E) is 103-GPa.

Now, we want to find the maximum load that may be applied to a specimen with a cross-sectional area of 130-mm² without plastic deformation. Thus;

We are given the parameters;

Yield Stress; σ = 345 Mpa = 345 * 10⁶ Pa

Elastic Modulus; E = 103 GPa = 103 * 10⁹ Pa

Cross sectional Area; A = 130 mm² = 103 * 10⁻⁶ m²

Formula for stress without Plastic deformation is;

σ = F_max/Area

where;

σ is stress

F_max is maximum force

Area is Area

Thus making maximum force the subject of the formula gives;

F_max = σ * A

Plugging in the relevant values for stress and area gives us;

F_max = 345 * 10⁶ * 103 * 10⁻⁶

F_max = 35535 N

The maximum load that may be applied to a specimen with a cross-sectional area of 130 mm² is gotten to be 35535 N

Read more about Elastic Modulus at; brainly.com/question/6864866

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4 0

2 years ago