Question

A sample of oxygen gas (O2) has a volume of 7.51 L at a temperature of 19°C and a pressure of 1.38 atm. Calculate the moles of O2 molecules present in this gas sample.

Answer 1

Answer: 0.43molO₂

Explanation:

The ideal gas law for moles is $n=\frac{PV}{RT}$. If you did not know, R is the ideal gas constant, $0.0821\frac{L*atm}{mol*K}$.

Since the temperature must be in Kelvin, we must convert our given temperature from ℃ to K. $19C+273=292K$

Now that we have the temperature converted to Kelvin, we can plug in our information to the ideal gas law for the number of moles.

$n=\frac{PV}{RT}$

$n=\frac{1.38atm*7.51L}{0.0821\frac{L*atm}{mol*K} *292K} =0.43molO_{2}$

$n=0.43molO_{2}$

Therefore, the number of moles is 0.43molO₂.

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