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mart [117]
2 years ago
12

How many liters of a 0.80 M solution can be made with 2.0 mol KNO3?

Chemistry
1 answer:
kvasek [131]2 years ago
3 0

Answer:

Solution

Verified by Toppr

2 molL

−1

Explanation :

Concentration =

Volume of solution

Moles of solute

We assume that potassium nitrate dissolves in the given volume of solvent without gross change in volume.

Concentration =

101.10gmol

−1

404g

×

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PLEASE HELP
Rudik [331]

Answer

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Explanation:

hope this helps ! :)

7 0
3 years ago
How many moles of helium are needed to fill a balloon to a volume of 5.3 L at 22 ℃ and 632 mmHg?
son4ous [18]

Answer:

0.18 moles

Explanation:

Applying,

PV = nRT................... Equation 1

Where P = pressure, V = volume, n = number of moles, R = molar gas constant, T = temperature.

make n the subject of the equation

n = PV/RT............... Equation 2

Given: V = 5.3 L, T = 22 °C = (22+272) K = 295 K, P = 632 mmHg = (0.00131579×632) = 0.8316 atm,  R = 0.083 L.atm/K.mol

Substitute these values into equation 2

n = (0.8316×5.3)/(0.083×295)

n = 0.18 moles

6 0
3 years ago
What mass of solid that has a molar mass of 46.0 g/mol should be added to 150.0 g of benzene to raise the boiling point of benze
enyata [817]

Answer : 17.12 g

Explanation:\Delta T =k_b\times m

\Delta T = elevation in boiling point

k_b = boiling point elevation constant

m= molality

molality=\frac{mass of solute}{molecular mass of solute\times weight of the solvent in kg}

given \Delta T=6.28^{\circ}C

Molar mass of solute = 46.0 gmol^{-1}

Weight of the solvent = 150.0 g = 0.15 kg

Putting in the values

molality=\frac{x}{46gmol^{-1}\times0.15kg}

6.28 =2.53^{\circ}Ckgmol^{-1}\frac{x}{46gmol^{-1}\times 0.15kg}

x = 17.12 g



3 0
3 years ago
Why do magnesium, phosphorus, and zinc exhibit slightly higher first ionization energies than the general trend within each of t
Lapatulllka [165]
Because they are farther across the periodic table<span />
8 0
3 years ago
PH + pOH = 14. What is the hydroxide concentration of a solution with pH of 8?
sladkih [1.3K]
PH + pOH = 14
pOH=14-8=4
(OH-)=10^-4
4 0
3 years ago
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