The explanation is shown in the image attached with
Answer:
118.06 mL
Explanation:
The neutralization reaction between HBr (acid) and Ba(OH)₂ (base) is the following:
2HBr + Ba(OH)₂ → BaBr₂ + 2H₂O
According to the equation, 2 moles of HBr react with 1 mol Ba(OH)₂. Thus, at the equivalence point the moles of acid and base react completely:
2 moles HBr = 1 mol Ba(OH)₂
We can replace the moles by the product of the molar concentration (M) and volume (V):
2 x (M HBr) x (V HBr) = M Ba(OH)₂ x V Ba(OH)₂
Now, we introduce the data in the equation to calculate the volume in mL of Ba(OH)₂:
V Ba(OH)₂ = (2 x (M HBr) x (V HBr))/M Ba(OH)₂
= (2 x 0.311 M x 57.7 mL)/(0.304 M)
= 118.06 mL
Therefore, 118 mL of Ba(OH)₂ are needed.
The number in Kg of oxygen that are present in the room is
403.1209 kg
<em><u>calculation</u></em>
mass=density x volume
density = 0.001429 g/ cm³
volume =775 cm x 1400 cm x 260 cm =2.821 x10^8 cm³
mass =0.001429 g/cm³ x( 2.8 x 10^8 cm³) =403120.9 grams
convert g to Kg
that is 1 kg = 1000 g
? kg =403120.9 g
by cross multiplication
=[(403120.9 g x 1 kg) /1000 g] =403.1209 kg
They are arranged differently, in diamonds they are interconnected bonds and in graphite they are arranged as sheets.
Answer:
<u><em> 15.9 KJ/mol</em></u>
Explanation:
Given data:
Temperature = T1 = 307 K
Temperature = T2 = 343 K
Gas constant R= 8.314 J/(mol • K)
rate constant = k2/K1 = 89
To find:
Activation energy (in kJ/mol) = Ea = ?
Formula:
The Arrhenius equation gives the relation between temperature and reaction rates:
here, in this equation
k = the rate constant
Ea = the activation energy
R = the Universal Gas Constant
T= the temperature
Solution:
ln 89 = Ea / 8.314 J/mol.K x (0.0325 - 0.00291)
ln 89 = Ea / 8.314 J/mol.K x (2.95 x 10^2 )
4.488 = Ea / 8.314 J/mol.K x (2.95 x 10^2)
Ea = 4.488 x (2.95 x 10^2) / 8.314 J/mol.K
= 0.1324 / 8.314
Ea = 0.0159
Ea = 1.59 x 10^2 J/mol
= 15.9 KJ/mol
