<span>Microscopic foreign particles that droplets form on is called the hygroscopic nuclei. The particles are already present in the air in the form of dust, salt from seawater evaporation and combustion residue. Together the particles begin the forming process of droplets.</span>
Answer:
a) 0.000112 M/s is the average reaction rate between 0.0 seconds and 1500.0 seconds.
b) 0.00011 M/s is the average reaction rate between 200.0 seconds and 1200.0 seconds.
c) Instantaneous rate of the reaction at t=800 s :
Instantaneous rate : ![\frac{0.031 M}{800.0 s}=3.875\times 10^{-5} M/s](https://tex.z-dn.net/?f=%5Cfrac%7B0.031%20M%7D%7B800.0%20s%7D%3D3.875%5Ctimes%2010%5E%7B-5%7D%20M%2Fs)
Explanation:
Average rate of the reaction is given as;
![R_{avg}=-\frac{\Delta A}{\Delta t}=\frac{A_2-A_1}{t_2-t_1}](https://tex.z-dn.net/?f=R_%7Bavg%7D%3D-%5Cfrac%7B%5CDelta%20A%7D%7B%5CDelta%20t%7D%3D%5Cfrac%7BA_2-A_1%7D%7Bt_2-t_1%7D)
a.) The average reaction rate between 0.0 s and 1500.0 s:
At 0.0 seconds the concentration was = ![A_1=0.184 M](https://tex.z-dn.net/?f=A_1%3D0.184%20M)
![t_1=0.0s](https://tex.z-dn.net/?f=t_1%3D0.0s)
At 1500.0 seconds the concentration was = ![A_2=0.016 M](https://tex.z-dn.net/?f=A_2%3D0.016%20M)
![t_2=1500 s](https://tex.z-dn.net/?f=t_2%3D1500%20s)
![R_{avg]=-\frac{0.016 M-0.184 M}{1500.0 s-0.0 s}=0.000112 M/s](https://tex.z-dn.net/?f=R_%7Bavg%5D%3D-%5Cfrac%7B0.016%20M-0.184%20M%7D%7B1500.0%20s-0.0%20s%7D%3D0.000112%20M%2Fs)
0.000112 M/s is the average reaction rate between 0.0 seconds and 1500.0 seconds.
b.) The average reaction rate between 200.0 s and 1200.0 s:
At 0.0 seconds the concentration was = ![A_1=0.129 M](https://tex.z-dn.net/?f=A_1%3D0.129%20M)
![t_1 =200.0 s](https://tex.z-dn.net/?f=t_1%20%3D200.0%20s)
At 1500.0 seconds the concentration was = ![A_2=0.019M](https://tex.z-dn.net/?f=A_2%3D0.019M)
![t_2=1200 s](https://tex.z-dn.net/?f=t_2%3D1200%20s)
![R_{avg]=-\frac{0.019 M-0.129M}{1200.0s-200.0s}=0.00011 M/s](https://tex.z-dn.net/?f=R_%7Bavg%5D%3D-%5Cfrac%7B0.019%20M-0.129M%7D%7B1200.0s-200.0s%7D%3D0.00011%20M%2Fs)
0.00011 M/s is the average reaction rate between 200.0 seconds and 1200.0 seconds.
c.) Instantaneous rate of the reaction at t=800 s :
At 800 seconds the concentration was = ![A=0.031 M](https://tex.z-dn.net/?f=A%3D0.031%20M)
![t =800.0 s](https://tex.z-dn.net/?f=t%20%3D800.0%20s)
Instantaneous rate : ![\frac{0.031 M}{800.0 s}=3.875\times 10^{-5} M/s](https://tex.z-dn.net/?f=%5Cfrac%7B0.031%20M%7D%7B800.0%20s%7D%3D3.875%5Ctimes%2010%5E%7B-5%7D%20M%2Fs)
Answer:
what is the question you are asking
Answer:
1) FALSE
2) TRUE
3) FALSE
4) FALSE
5) TRUE
Explanation:
<em>1)</em> The first excited state corresponds to n=3. <em>FALSE. </em>The ground state corresponds to n=1 and first excited state corresponds to n=2.
<em>2)</em> The wavelength of light emitted when the electron drops from n=3 to n=2 is shorter than the wavelength of light emitted if the electron falls from n=3 to n=1. <em>TRUE. </em>As the n=2 state is in a higher energy than n=1, the energy difference between n=2 and n=3 are shorter than differences between n=1 and n=3 states.
<em>3)</em> It takes more energy to ionize the electron from n=3 than it does from the ground state. <em>FALSE. </em>An electron with a high energy will be less-atracted by the nucleus than a electron with a low energy because is farther of it.
<em>4)</em> The wavelength of the light emitted when the electron returns to the ground state from n=3 is larger than the wavelength of light absorbed to go from n=1 to n=3. <em>FALSE. </em>The energy differences in light emitted and light absorbed is the same.
<em>5)</em> The electron is farther from the nucleus on average in the n=3 state than in the ground state. <em>TRUE. </em>According Bohr's model, the greater energy level, the farther from the nucleus it is.
I hope it helps!