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GuDViN [60]
2 years ago
9

11. A quiz has 10 multiple choice questions with 3 choices for each question. Answer the following for someone who randomly choo

ses answers to the questions.
a. Find the probability for getting exactly 4 correct answers.

Answer: ________________








b. Find the probability for getting at least 2 correct answers.

Answer: ________________









c. Find the probability for getting 2 or 3 incorrect answers.

Answer: ________________
Mathematics
1 answer:
11111nata11111 [884]2 years ago
4 0

The required probability for
a. 0.2058
b. 0.98  
c.0.016

<h3>
What is probability?</h3>

Probability can be defined as the ration of favorable outcomes to the total number of events.

Let use binomial distribution.
Probability answering a question correctly=1/3 =0.33
Probability of not answering a question correctly
=1–1/3
=2/3
a) Out of 10 probability of answering 4 correctly

=10c4 x (0.33)^4 x (0.66)^6

Upon simplification, 0.2058

b) Find the probability for getting at least 2 correct answers
= 1 - { 10c8 x (0.33)^8 x (0.66)^2+ 10c9 x (0.33)^9 x (0.66)^1 + (0.33)^10}
= 0.98

c).Find the probability for getting 2 or 3 incorrect answers.


10c8 x (0.33)^8 x (0.66)^2 + 10c7 x (0.33)^7 X (0.66)^3
=0.002 + 0.014

= 0.016

Thus the required probabilities are: 0.2058, 0.98 , 0.016

Learn more about probability here:

brainly.com/question/14290572

#SPJ1


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For what values of x is f(x) = |x + 1| differentiable? I'm struggling my butt off for this course
pav-90 [236]

By definition of absolute value, you have

f(x) = |x+1| = \begin{cases}x+1&\text{if }x+1\ge0 \\ -(x+1)&\text{if }x+1

or more simply,

f(x) = \begin{cases}x+1&\text{if }x\ge-1\\-x-1&\text{if }x

On their own, each piece is differentiable over their respective domains, except at the point where they split off.

For <em>x</em> > -1, we have

(<em>x</em> + 1)<em>'</em> = 1

while for <em>x</em> < -1,

(-<em>x</em> - 1)<em>'</em> = -1

More concisely,

f'(x) = \begin{cases}1&\text{if }x>-1\\-1&\text{if }x

Note the strict inequalities in the definition of <em>f '(x)</em>.

In order for <em>f(x)</em> to be differentiable at <em>x</em> = -1, the derivative <em>f '(x)</em> must be continuous at <em>x</em> = -1. But this is not the case, because the limits from either side of <em>x</em> = -1 for the derivative do not match:

\displaystyle \lim_{x\to-1^-}f'(x) = \lim_{x\to-1}(-1) = -1

\displaystyle \lim_{x\to-1^+}f'(x) = \lim_{x\to-1}1 = 1

All this to say that <em>f(x)</em> is differentiable everywhere on its domain, <em>except</em> at the point <em>x</em> = -1.

4 0
3 years ago
PLS HELLP PLS PLS
Andrew [12]

Answer:

it would be 100 rounded because 14x8=112 and 112 is rounded to 100 to the nearest hundreth. Please subscribe to Amiredagoat Yt

Step-by-step explanation:

6 0
2 years ago
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tatiyna
3738383792639263846736283
5 0
2 years ago
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The equation represents an ellipse. which points are the vertices of the ellipse? (7, 1) and (7, −5) (7, −10) and (7, 6) (10, −2
OleMash [197]

The points which represents the vertices of the given equation are; (15, −2) and (−1, −2).

<h3>Which points among the answer choices represents the vertices of the ellipse whose equation is given?</h3>

The complete question gives the equation of the ellipse as; (x-7)²/64+(y+2)²/9=1.

Since, It follows from convention that general equation of ellipse with centre as (h, k) takes the form;

(x-h)²/a² +(y-k)²/b² = 1.

Consequently, it follows from observation that the value of a and b in the given equation in the task content is; √64 = 8 and √9 = 3 respectively.

Since, 8 > 3, The vertices of the ellipse are given by; (h±a, k).

The vertices in this scenario are therefore;

(7+8, -2) and (7-8, -2).

= (15, -2) and (-1, -2).

Read more on vertices of an ellipse;

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7 0
1 year ago
Apples are 94 cents a pound, and pears are $1.22 a pound. write an expression for the total cost, in dollars, of a pounds of app
sineoko [7]
1 apple: 94 cents = 0.94 dollars
a apples: 0.94 ×a= 0.94a
p pears: 1.22× p= 1.22p
total: 1.22p + 0.94a
hope it helps!
4 0
2 years ago
Read 2 more answers
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