Answer:
4.25m
Explanation:
Joules is a "derived unit", meaning it is really composed of other units, and it is just abbreviated as a single letter.
![1[J]=1 [\frac{kg \cdot m^2}{s^2}]](https://tex.z-dn.net/?f=1%5BJ%5D%3D1%20%5B%5Cfrac%7Bkg%20%5Ccdot%20m%5E2%7D%7Bs%5E2%7D%5D)
This comes from the formula for potential energy, often denoted "U"
, where m is the mass of the object (measured in kilograms,
), g is the acceleration due to gravity at that spot (measured in meters per second squared,
), and h is the height of the object (measured in meters,
).
<em>Note: The object itself may or may not have an acceleration of "g" at the given point because it may be supported (like on a bookshelf). However, the "g" is representative of its gravitational acceleration at that point if gravity could accelerate it unimpeded.</em>
Rearranging the potential energy equation to isolate the unknown "h", dividing both sides by "m" and "g", we get the following:

Substituting known values (and rewriting Joules as its SI units so we can ensure units cancel the way we need them to):
![\dfrac{\left (50 [\frac{kg \cdot m^2}{s^2}] \right)}{(1.2 [kg])(9.8 [\frac{m}{s^2}])}=h\\\dfrac{\left (50 [\frac{kg \!\!\!\!\!\!\!{--} \cdot m^{2 \!\!\!{-}}}{s^2\!\!\!\!\!\!\!{--} }] \right)}{(1.2 [kg \!\!\!\!\!\!\!{--} ])(9.8 [\frac{m\!\!\!\!\!\!\!{--} }{s^2\!\!\!\!\!\!\!{--} }])}=h\\\dfrac{(50)}{(1.2)(9.8)}[m]=h\\\\4.2517[m] \approx h](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cleft%20%2850%20%5B%5Cfrac%7Bkg%20%5Ccdot%20m%5E2%7D%7Bs%5E2%7D%5D%20%5Cright%29%7D%7B%281.2%20%5Bkg%5D%29%289.8%20%5B%5Cfrac%7Bm%7D%7Bs%5E2%7D%5D%29%7D%3Dh%5C%5C%5Cdfrac%7B%5Cleft%20%2850%20%5B%5Cfrac%7Bkg%20%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%7B--%7D%20%5Ccdot%20m%5E%7B2%20%5C%21%5C%21%5C%21%7B-%7D%7D%7D%7Bs%5E2%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%7B--%7D%20%7D%5D%20%5Cright%29%7D%7B%281.2%20%5Bkg%20%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%7B--%7D%20%5D%29%289.8%20%5B%5Cfrac%7Bm%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%7B--%7D%20%7D%7Bs%5E2%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%7B--%7D%20%7D%5D%29%7D%3Dh%5C%5C%5Cdfrac%7B%2850%29%7D%7B%281.2%29%289.8%29%7D%5Bm%5D%3Dh%5C%5C%5C%5C4.2517%5Bm%5D%20%5Capprox%20h)
Thus, the height of the book would be approximately 4.25meters high.