Respiratory and circulatory
The equation to be used here is the trajectory of a projectile as written below:
y = xtanθ +/- gx²/2v²(cosθ)²
where
y is the vertical distance
x is the horizontal distance
θ is the angle of trajectory or launch angle
g is 9.81 m/s²
v is the initial velcity
Since the angle is below horizontal, let's use the minus equation. Substituting the values:
- 0.8 m = xtan15° - (9.81 m/s²)x²/2(4.8 m/s)²(cos15°)²
Solving for x,
x = 2.549 m
However, we only take half of this distance because it was specified that the distance asked before bouncing. Hence, the horizontal distance is equal to 1.27 m.
Force = (mass) · (acceleration)
= (1,000 kg) · (9.8 m/s²)
= 9,800 newtons
Why are you still having a problem with F = M · a ?
Answer: The complexity of filter is the order of the filter. Greater the order of the filter, more efficient the filter is. Roll of value of one filter is 20dB/dec. So the roll-off value of 8th order filter is 160dB/dec. 8th order filter is more efficient than the second order low-pass filter.
Answer:
The acceleration of a boat if the resultant force on it is 4000 N and its mass is 1240 kg is 3.2 m/s².
Explanation:
Given
To determine
Acceleration a = ?
Important Tip:
- The acceleration of a boat can be found using the formula F = ma
Using the formula
where
- a is the acceleration (m/s²)
now substituting F = 4000, m = 1240 in the formula
Switch sides
Divide both sides by 1240
Simplify
m/s²
Therefore, the acceleration of a boat if the resultant force on it is 4000 N and its mass is 1240 kg is 3.2 m/s².
