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3 years ago

What is the force on a 1,000 kilogram-elevator that is falling freely under the acceleration of gravity only?

1 answer:

8 0

   Force = (mass) · (acceleration)

   = (1,000 kg) · (9.8 m/s²)

   = 9,800 newtons

Why are you still having a problem with F = M · a ?

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What do any two samples of the element mercury (Hg) have in common?

Bas_tet [7]

A shiny surface,atomic number 80 and its <span>symbol is </span>Hg<span> </span>

5 0

3 years ago

A mass suspended from a spring bobs up and down one complete cycle every 2 s. its period is?

lilavasa [31]

The period is 2 seconds.

A period is a time taken to make one simple harmonic motion. It can be described as time divided by how many waves do. We can write the period formula as

T = t / n

where T is period, t is time and n is the amount of simple harmonic motions.

From the question above, we know that the mass travel up and down, it means that the cycle is one simple harmonic motion.

n = 1

t = 2s

Hence

T = t / n

T = 2 / 1

T = 2 second

For more on period at: brainly.com/question/24255969

#SPJ4

4 0

2 years ago

In Millikan's experiment, an oil drop of radius 1.362 μm and density 0.888 g/cm3 is suspended in chamber C when a downward-point

Misha Larkins [42]

Answer:

The charge on the oil drop is 3e

Explanation:

F = qE

Where;

F is the applied force in Newton

E is the electric field potential N/C

q is charge in C

Given;

Radius, r = 1.362 μm = 1.362 X 10⁻⁶ m

density, ρ = 0.888 g/cm³ = 0.888 X 10³ kg/m³

Electric field potential = 1.92 ✕ 10⁵ N/C

F =mg

mass of the oil drop = density, ρ X volume of the oil drop

volume of the oil drop (spherical) = (4/3)πr³ = 1.3333π(1.362 X 10⁻⁶)³

⇒ volume of the oil drop = 10.584 X 10⁻¹⁸ m³

mass of the oil drop = 0.888 X 10³ (kg/m³) X 10.584 X 10⁻¹⁸ (m³)

⇒ mass of the oil drop = 9.399 X 10⁻¹⁵ kg

⇒ F =mg = 9.399 X 10⁻¹⁵ kg X 9.8 = 9.21 X10⁻¹⁴ N

F = qE

q = F/E

q = (9.21 X10⁻¹⁴)/(1.92 ✕ 10⁵) = 4.797 X 10⁻¹⁹ C

In terms of e

1e = 1.6 X10⁻¹⁹ C

= (4.797 X 10⁻¹⁹ C)/(1.6 X10⁻¹⁹ C) = 3e

Therefore, the charge on the oil drop is 3e

7 0

3 years ago

Like charges will exert a force of

natulia [17]

Answer:

D- Repulsion

Explanation:

A positively charged object will exert a repulsive force upon a second positively charged object.

7 0

3 years ago

Read 2 more answers

A disk of a radius 50 cm rotates at a constant rate of 100 rpm. What distance in meters will a point on the outside rim travel d

Iteru [2.4K]

Answer:

A point on the outside rim will travel 157.2 meters during 30 seconds of rotation.

Explanation:

We can find the distance with the following equation since the acceleration is cero (the disk rotates at a constant rate):

$d = v*t$

Where:

v: is the tangential speed of the disk

t: is the time = 30 s

The tangential speed can be found as follows:

$v = \omega*r$

Where:

ω: is the angular speed = 100 rpm

r: is the radius = 50 cm = 0.50 m

$v = \omega*r = 100 \frac{rev}{min}*\frac{2\pi rad}{1 rev}*\frac{1 min}{60 s}*0.50 m = 5.24 m/s$

Now, the distance traveled by the disk is:

$d = v*t = 5.24 m/s*30 s = 157.2 m$

Therefore, a point on the outside rim will travel 157.2 meters during 30 seconds of rotation.

I hope it helps you!

3 0

3 years ago