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Lapatulllka [165]
2 years ago
9

The detonation of some amount of TNT causes the volume of nearby gas to increase from 10.0 L to 90.0 L (the pressure remains con

stant at 1.00 atm). Additionally, 90.0 kJ of energy is released as heat during the detonation. What is of the TNT in kilojoules for this process
Chemistry
1 answer:
Gnom [1K]2 years ago
6 0

Internal combustion energy for TNT(Trinitro toluene) is found to be  -170 kJ.

Internal energy= (- heat evolved by the system) + Work done by the system

ΔU = -Q+W

W = - PΔV

P= pressure

ΔV =difference in volume

Given,

V1 = 10 L

V2 = 90 L

∴ΔV = V2-V1 = 90-10 = 80 L

P = 1 atm

∴W = - ( 1× 80)

      = -80 kJ

Heat evolved by the system = 90 kJ

∴Δ U= - 90 kJ - 80 kJ

       = - 170 kJ

Thus, Internal combustion energy for TNT(Trinitro toluene) is found to be -170 kJ.

NOTE : here work done by the system is considered negative and also heat evolved by the system is taken -Ve.

Learn more about internal energy here..

brainly.com/question/1370118

#SPJ4

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Answer:

The gas will occupy a volume of 1.702 liters.

Explanation:

Let suppose that the gas behaves ideally. The equation of state for ideal gas is:

P\cdot V = n\cdot R_{u}\cdot T (1)

Where:

P - Pressure, measured in kilopascals.

V - Volume, measured in liters.

n - Molar quantity, measured in moles.

T - Temperature, measured in Kelvin.

R_{u} - Ideal gas constant, measured in kilopascal-liters per mole-Kelvin.

We can simplify the equation by constructing the following relationship:

\frac{P_{1}\cdot V_{1}}{T_{1}} = \frac{P_{2}\cdot V_{2}}{T_{2}} (2)

Where:

P_{1}, P_{2} - Initial and final pressure, measured in kilopascals.

V_{1}, V_{2} - Initial and final volume, measured in liters.

T_{1}, T_{2} - Initial and final temperature, measured in Kelvin.

If we know that P_{1} = 121\,kPa, P_{2} = 202\,kPa, V_{1} = 2.7\,L, T_{1} = 288\,K and T_{2} = 303\,K, the final volume of the gas is:

V_{2} = \left(\frac{T_{2}}{T_{1}} \right)\cdot \left(\frac{P_{1}}{P_{2}} \right)\cdot V_{1}

V_{2} = 1.702\,L

The gas will occupy a volume of 1.702 liters.

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