Answer:
6 seconds
Explanation:
Since the object is being dropped out of the window, it has no initial velocity.
Hope this helps!
The negative sign on the acceleration is only a vector quantity that means the object is accelerating to the left. Hence, we can only focus on it magnitude which is 4 m/s^2. Acceleration is the change in velocity over time. The change in velocity must be 24 m/s - 0 m/s, if you want the object to stop. Therefore,
a = (v2 - v1)/t
4 = (24 - 0)t
t = 6 seconds
The object will stop after 6 seconds.
Answer:
Assuming the charged density in the insulated solid sphere of radius 3.1m is 8.8e-9, the electric field at 5.2 meters is 73.1256 .
Explanation:
The electric charge linear density is equal to 8.8 x
the radius of the sphere is 3.1m
The magnitude of the electric field at the radius of the sphere equal to 5.2 meters can be calculated with the formula ;
- E = λ / 4πε₀ [ r / α ( α + r ) ]
Solution:
E = 8.8 x / 4πε₀ [ 3.1/ 5.2( 5.2 + 3.1) ]
= 1018.0995 [0.07183]
= 73.1256
Wavelength should be in meters which is 0.023 m
c = 3.7 * 0.023 = 0.0851 (3 sf)