Answer:
Both are pure substances and a compound
First, determine the number of moles of gold.
Number of moles = 
Given mass of gold =
Molar mass of gold = 196.97 g/mol
Put the values,
Number of moles of gold = 
=
or
Now, molarity = 
Put the values, volume of ocean =
Molarity = 
= 
Thus, average molar concentration = 
Answer:
The Electron Configuration for Sulfur(S)= 1s^2 2s^2 2p^6 3s^2 3p^4
Explanation:
Use the sheet attached to help with a future question. (Hint: Follow the red lines). The atomic number will be equal to the number of powers raised.
You would first do research. (d)
The research part will help you find what ideas worked and what ideas didn't work.