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Nina [5.8K]
3 years ago
9

A 190 g rock at 20°C is completely immersed in 600 g of water at 80°C. Which one of the following statements is true right after

the rock goes in?
A. The water gives the rock thermal energy and gets no thermal energy in return.
B. The rock and the water give each other thermal energy, but the water gives more than it gets.
C. The rock gives the water thermal energy and gets no thermal energy in return.
D. It depends on the specific heat of the rock.
E. The rock and the water give each other thermal energy, but the rock gives more than it gets
Physics
1 answer:
Umnica [9.8K]3 years ago
8 0

Rock is completely immersed in hot water. By the second law of thermodynamics, thermal energy or heat is transferred from substance with higher temperature to substance with lower temperature until they come to thermal equilibrium i.e. both at same temperature.

It is given here that rock is at 20°C which is at lower temperature than water at 80°C. ∴Heat or thermal energy flows from water to rock. So, right choice is-

A. The water gives the rock thermal energy and gets no thermal energy in return.

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Pressure is about 1000 hPa at sea level and about 500 hPa at an altitude of 5.5 km. Why doesn’t this vertical pressure gradient
saul85 [17]

Answer:

A. The upward pressure gradient force is balanced by gravity.

Explanation:

A. is correct because the pressure difference is actually generated by gravity. As in the following formula for the pressure at different points:

p = p_0 + \rho g h

where p, p_0 are the pressure at 2 points, ρ is the density of the fluid, g is the gravitational constant, and h is the height difference.

B is incorrect because friction in air is too small to make an effect.

C is incorrect because the Coriolis force is horizontal, not vertical.

D is incorrect because a difference of 500 hPa = 50000 Pa, this is half of the atmospheric pressure.

E is incorrect because temperature cannot generate force.

6 0
3 years ago
Un Esquiador Inicia un Salto Horizontal con una velocidad Inicial de 25 m/s. La Altura al Final de la Rampa es de 80 m del punto
Evgesh-ka [11]

Responder:

Explicación:

Para que podamos calcular el tiempo que le tomará al esquiador permanecer en el aire, encontraremos el tiempo de vuelo como se muestra;

T = 2Usin theta / 2

theta = 90 grados

U = 25 m / s

T = 25sin90 / 2 (9,8)

T = 25 / 19,62

T = 1,27 segundos

Por lo tanto, los cielos usarán 1.27 segundos en el aire.

La distancia horizontal es el rango;

Rango R = U√2H / g

R = 25√2 (80) /9,8

R = 25√160 / 9,8

R = 25 * √16,326

R = 25 * 4.04

R = 101,02 m

Por tanto, la distancia horizontal recorrida por el esquiador es 101,02 m

5 0
3 years ago
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Korvikt [17]

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Consider two buildings as a single slit, for single slit diffraction dark fringes are located an angle of

\theta _{p}=sin^{-1}\frac{\lambda}{a}

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For the first dark fringes

\theta _{1}=sin^{-1}\frac{\lambda}{a}\\\theta _{1}=sin^{-1}\frac{0.3614}{15}\\\theta _{1}=1.38^{0}

Angular width of the electromagnetic wave after it emerges from between the buildings is

\Delta\theta =2\theta _{1}\\\Delta\theta =2\times 1.38\\\Delta\theta =2.761^0

6 0
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