A nuclear reaction must lead to changes in the nucleus of an atom.
<h3>What is a nuclear reaction?</h3>
The term nuclear reaction refers to a reaction in which a new nucleus is formed. The following are the nuclear reactions;
a) 60/27Co -----> 60/28 Ni + 0/-1 e
b) 241/95 Am ------> 237/93Np + 4/2He
c) 60/29 ----> 60/28 Ni + 0/1 e
d) 66/31 Ga + 0/-1 e -----> 66/30 Zn
Learn more about nuclear reactions:brainly.com/question/16526663
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Answer:
Final Volume = 5.18 Liters
Explanation:
Initial Condition:
P1 = 789 mm Hg x (1/760) atm /mm Hg = 1.038 atm
T1 = 22° C = 273 + 22 = 295 K
V1 = 4.7 L
Final Condition:
P2 = 755 mm Hg x (1/760) atm /mm Hg = 0.99 atm
T2 = 37° C = 273 + 37 = 310 K
V2 = ?
Since, (P1 x V1) / T1 =  (P2 x V2) / T2,
Therefore,
⇒ (1.038)(4.7) / 295 = (0.99)(V2) / 310
⇒ V2 = 5.18 L (Final Volume)
 
        
             
        
        
        
Answer:
yes
Explanation:
Usually, it would not affect the crucible, but depending on the temperature of the flame the enamel of the crucible may begin to melt and stick to the metal object being used to handle the crucible. This tiny amount that is melted off can cause very small changes in the original mass of the crucible, which although it is almost unnoticeable it is still there. Therefore, the answer to this question would be yes.
 
        
             
        
        
        
5.6 Al(OH)3
5.6 Al, 16.8 O, 16.8 H
16.8 mols of oxegyn in 5.6 mols of Al(OH)3
        
             
        
        
        
Answer:
Compound X has a molar mass of 316.25 g*mol^-1 and the following composition:
element & mass %
phosphorus & 39.18%
sulfur & 60.82%
Write the molecular formula of X.
Explanation:
The given molecule of phosphorus and sulfur has molar mass --- 316.25 g.
Empirical formula calculation:                       
element:              phosphorus                       sulfur 
co9mposition:      39.185%                            60.82%
divide with 
atomic mass:          39.185/31.0 g/mol           60.82/32.0g/mol
                               =1.26mol                           1.90mol
smallest mole ratio:   1.26mol/1.26mol =1      1.90mol/1.26 mol =1.50
multiply with 2:          2                                         3
Hence, the empirical formula is:
P2S3.
Mass of empirical formula is:
158.0g/mol
Given, molecule has molar mass --- 316.25 g/mol
Hence, the ratio is:
316.25g/mol/158.0 =2
Hence, the molecular formula of the compound is :
2 x (P2S3)
=