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Furkat [3]
2 years ago
10

Tin is used to coat tin cans for food storage. If the tin is scratched and the iron of the can exposed, will the iron corrode mo

re rapidly or less rapidly? Explain
Chemistry
1 answer:
ivann1987 [24]2 years ago
6 0

The scratched tin can with the iron will more rapidly corrode the iron than the tin.

<h3>What is corrosion?</h3>

The corrosion can be given as the process of the oxidation of the metal into the more stable metal oxide. The chemical oxidation of the metal is attained with the surrounding available oxygen or the water vapors.

The reactivity of the Iron for the oxidation is more as compared to the tin from the reactivity series. Therefore if both tin and iron are exposed to corrosion, iron will be more rapidly corroded.

Learn more about corrosion, here:

brainly.com/question/489228

#SPJ1

You might be interested in
2. Write balanced chemical reactions for the following: (1 point each, 4 points total) a. Cobolt-60 undergoes beta decay b. Amer
kondaur [170]

A nuclear reaction must lead to changes in the nucleus of an atom.

<h3>What is a nuclear reaction?</h3>

The term nuclear reaction refers to a reaction in which a new nucleus is formed. The following are the nuclear reactions;

a) 60/27Co -----> 60/28 Ni + 0/-1 e

b) 241/95 Am ------> 237/93Np + 4/2He

c) 60/29 ----> 60/28 Ni + 0/1 e

d) 66/31 Ga + 0/-1 e -----> 66/30 Zn

Learn more about nuclear reactions:brainly.com/question/16526663

#SPJ1

5 0
2 years ago
If 4.70 L of CO2 gas at 22 ∘C at 789 mmHg is used, what is the final volume, in liters, of the gas at 37 ∘C and a pressure of 75
lutik1710 [3]

Answer:

Final Volume = 5.18 Liters

Explanation:

Initial Condition:

P1 = 789 mm Hg x (1/760) atm /mm Hg = 1.038 atm

T1 = 22° C = 273 + 22 = 295 K

V1 = 4.7 L

Final Condition:

P2 = 755 mm Hg x (1/760) atm /mm Hg = 0.99 atm

T2 = 37° C = 273 + 37 = 310 K

V2 = ?

Since, (P1 x V1) / T1 =  (P2 x V2) / T2,

Therefore,

⇒ (1.038)(4.7) / 295 = (0.99)(V2) / 310

⇒ V2 = 5.18 L (Final Volume)

5 0
3 years ago
A cool, yellow-orange flame is used to heat the crucible. Would this affect the mass of the crucible? If so, how?
s2008m [1.1K]

Answer:

yes

Explanation:

Usually, it would not affect the crucible, but depending on the temperature of the flame the enamel of the crucible may begin to melt and stick to the metal object being used to handle the crucible. This tiny amount that is melted off can cause very small changes in the original mass of the crucible, which although it is almost unnoticeable it is still there. Therefore, the answer to this question would be yes.

5 0
3 years ago
How many moles of oxygen are in 5.6 moles of al(oh)3?
Mashcka [7]
5.6 Al(OH)3
5.6 Al, 16.8 O, 16.8 H

16.8 mols of oxegyn in 5.6 mols of Al(OH)3
7 0
3 years ago
Compound X has a molar mass of 316.25 g*mol^-1 and the following composition:
Leokris [45]

Answer:

Compound X has a molar mass of 316.25 g*mol^-1 and the following composition:

element & mass %

phosphorus & 39.18%

sulfur & 60.82%

Write the molecular formula of X.

Explanation:

The given molecule of phosphorus and sulfur has molar mass --- 316.25 g.

Empirical formula calculation:                      

element:              phosphorus                       sulfur

co9mposition:      39.185%                            60.82%

divide with

atomic mass:          39.185/31.0 g/mol           60.82/32.0g/mol

                              =1.26mol                           1.90mol

smallest mole ratio:   1.26mol/1.26mol =1      1.90mol/1.26 mol =1.50

multiply with 2:          2                                         3

Hence, the empirical formula is:

P2S3.

Mass of empirical formula is:

158.0g/mol

Given, molecule has molar mass --- 316.25 g/mol

Hence, the ratio is:

316.25g/mol/158.0 =2

Hence, the molecular formula of the compound is :

2 x (P2S3)

=P_4S_6

8 0
3 years ago
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