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Furkat [3]
2 years ago
10

Tin is used to coat tin cans for food storage. If the tin is scratched and the iron of the can exposed, will the iron corrode mo

re rapidly or less rapidly? Explain
Chemistry
1 answer:
ivann1987 [24]2 years ago
6 0

The scratched tin can with the iron will more rapidly corrode the iron than the tin.

<h3>What is corrosion?</h3>

The corrosion can be given as the process of the oxidation of the metal into the more stable metal oxide. The chemical oxidation of the metal is attained with the surrounding available oxygen or the water vapors.

The reactivity of the Iron for the oxidation is more as compared to the tin from the reactivity series. Therefore if both tin and iron are exposed to corrosion, iron will be more rapidly corroded.

Learn more about corrosion, here:

brainly.com/question/489228

#SPJ1

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Calculate: (a) the weight (in lbf) of a 30.0 lbm object. (b) the mass in kg of an object that weighs 44N. (c) the weight in dyne
belka [17]

Answer:

a) 965,1 lbf

b) 4,5 kg

c) 1,33 * 10^6 dynes

Explanation:

Mass of an object refers to the amount of mattter it cotains, it can be expressed it gr, kg, lbm, ton, etc.

Weight of an object refers to a force, and is the measurement of the pull of gravitiy on an object. It may be definide as the mass times the acceleration of gravity.

                                        w=mg

In Planet Earth, the nominal "average" value for gravity is 9,8 m/s² (in the International  System) or 32,17 ft/s² (in the FPS system).

To solve this problem we'll use the following conversion factors:

1 lbf = 1 lbm*ft/s²

1 N = 1 kg*m/s²

1 dyne = 1 gr*cm/s²   and 1 N =10^5 dynes

1 ton = 907,18 kg

1 k = 1000 gr

a) m = 30 lbm

w = 30 lbm * 32,17 ft/s^{2} = 965, 1 \frac{lmb*ft}{s^{2} } = 965,1 lbf

b) w = 44 N

First, we clear m of the weight equation and then we replace our data.

m = \frac{w}{g} = \frac{44 N}{9,8 \frac{m}{{s}^{2}} } = 4,5 kg

c) m = 15 ton

m=15 ton * \frac{907,18 kg}{1 ton} = 13607,7 kg \\ w = mg = 13607,7 kg * 9,8 m/s2 = 133355,5 N * \frac{10^{5} dynes }{1 N} = 1,33 * 10^{6}dynes

4 0
4 years ago
Commercial concentrated aqueous ammonia is 28% nh3 by mass and has a density of 0.90 g/ml. what is the concentration of ammonia
patriot [66]

Answer:- 14.9 M

Solution:- Given commercial sample of ammonia is 28% by mass. Let's say we have 100 grams of the sample. Then mass of ammonia would be 28 grams.

Density of the solution is given as 0.90 grams per mL.

From the mass and density we could calculate the volume of the solution as:

100g(\frac{1mL}{0.90g})

= 111 mL

Let's convert the volume from mL to L as molarity is moles of solute per liter of solution.

111mL(\frac{1L}{1000mL})  

= 0.111 L

Now, we convert grams of ammonia to moles on dividing the grams by molar mass. Molar mass of ammonia is 17 gram per mole.

28g(\frac{1mole}{17g})

= 1.65 mole

To calculate the molarity we divide the moles of ammonia by the liters of solution:

molarity=\frac{1.65mole}{0.111L}

= 14.9 M

So, the molarity of the given commercial sample of ammonia is 14.9 M.

5 0
4 years ago
Why is there a difference in the conductivity of pure solid NaC1 and of the 1.0 M NaC1 soulution
Basile [38]
That would be cause part of the sodium is pure and that means it still kind of has it properties when it was an element and that its i think.
7 0
4 years ago
Explain how did you find the qostion
Alekssandra [29.7K]
What do you mean by this?
6 0
3 years ago
Please help me out with this question if you help me I will give you the brain thing and extra points. 8/9 image below.
Nataly [62]

Answer:

the answer is most likely b, sorry if im wrong.

Explanation:

.....

7 0
3 years ago
Read 2 more answers
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