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Furkat [3]
2 years ago
10

Tin is used to coat tin cans for food storage. If the tin is scratched and the iron of the can exposed, will the iron corrode mo

re rapidly or less rapidly? Explain
Chemistry
1 answer:
ivann1987 [24]2 years ago
6 0

The scratched tin can with the iron will more rapidly corrode the iron than the tin.

<h3>What is corrosion?</h3>

The corrosion can be given as the process of the oxidation of the metal into the more stable metal oxide. The chemical oxidation of the metal is attained with the surrounding available oxygen or the water vapors.

The reactivity of the Iron for the oxidation is more as compared to the tin from the reactivity series. Therefore if both tin and iron are exposed to corrosion, iron will be more rapidly corroded.

Learn more about corrosion, here:

brainly.com/question/489228

#SPJ1

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7 0
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There are over 100 elements, but only
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Answer:

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6 0
3 years ago
Choices for images
BabaBlast [244]

One

Let's start by stating what we know is wrong. Equilibrium is achieved when the reactants and products have a stable concentration. That makes D incorrect. Equilibrium is not established until about the 6th or 7th second.

The fact that you get any products at all means that the reactants will become products.  Just who is favored has to be looked at very carefully. The products start very near 0. They go up until their concentration at equilibrium. When the reach equilibrium, the products have increased to 17. The reactants have dropped from 40 to 27. By a narrow margin, I would say the products are favored.

C is incorrect. There are still reactants left.  

E is incorrect. the reactants started out with a concentration of 40. The reaction is not instantaneous.  The concentration was highest at 40 or right at the beginning. This assumes that the reactants were mixed and the products were produced and the water/liquid amount has not changed.

B is incorrect. The concentration of the reactants is higher at equilibrium.

A is wrong. It is product favored.

I'm getting none of the above.

Problem Two

AgBr is insoluble (very). You'd have to work very hard to get them to separate into their elemental form. Just putting AgBr in water isn't enough. Lots of heat and lots of electricity are needed to get the elemental form.

I suppose you should pick B. Mass must be preserved. But if you balanced the equation, it would work with heat and electricity.



3 0
3 years ago
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Answer:

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