The volume of a 14.00g of nitrogen at 5.64atm and 315K is 4.59L.
<h3>How to calculate volume?</h3>
The volume of an ideal gas can be calculated using the following ideal gas equation formula;
PV = nRT
Where;
- P = pressure (atm)
- V = volume (L)
- n = number of moles
- R = gas law constant
- T = temperature
An ideal gas is a hypothetical gas, whose molecules exhibit no interaction, and undergo elastic collision with each other and with the walls of the container.
The number of moles in 14g of nitrogen can be calculated as follows:
moles = 14g ÷ 14g/mol = 1mol
5.64 × V = 1 × 0.0821 × 315
5.64V = 25.86
V = 25.86 ÷ 5.64
V = 4.59L
Therefore, 4.59L is the volume of the gas
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The answer is (A).
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Answer: C. Europa Clipper
Explanation:
Answer:16.38085
Explanation:Aline the decimals then start multiplying.
<u>Answer:</u> The expression of
for calcium fluoride is ![K_{sp}=[Ca^{2+}][2F^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BCa%5E%7B2%2B%7D%5D%5B2F%5E-%5D%5E2)
<u>Explanation:</u>
Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.
The given chemical equation follows:

1 mole of calcium fluoride produces 1 mole of calcium ions and 2 moles of fluorine ions.
The expression of
for above equation follows:
![K_{sp}=[Ca^{2+}][2F^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BCa%5E%7B2%2B%7D%5D%5B2F%5E-%5D%5E2)
Hence, the expression of
for calcium fluoride is ![K_{sp}=[Ca^{2+}][2F^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BCa%5E%7B2%2B%7D%5D%5B2F%5E-%5D%5E2)