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aniked [119]
2 years ago
6

Explain how did you find the qostion

Chemistry
1 answer:
Alekssandra [29.7K]2 years ago
6 0
What do you mean by this?
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An increase in the ratio of insulin to glucagon will increase the activity of which of the following enzymes (+ indicates activi
AleksAgata [21]

Answer: An increase in the ratio of insulin to glucagon will increase the activity of --

- Acetyl-CoA carboxylase(+)

-Phosphofructokinase PFK2(+)

-Glycogen synthase(+)

- Hormone sensitive lipase (-). The hormone sensitive lipase activity is not increased with increased insulin activity.

Explanation: increased insulin - glucagon ratio is usually high in fed state.Insulin helps the cells absorb glucose, reducing blood sugar and providing the cells with glucose for energy. When blood sugar levels are too low, the pancreas releases glucagon. Glucagon instructs the liver to release stored glucose, which causes blood sugar to rise.

7 0
3 years ago
How much smaller is an electron than a proton​
meriva

Answer:

An electron is around 1800 times smaller than a proton

Explanation:

3 0
3 years ago
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Can an ionic bond exist in a molecular formula?
bogdanovich [222]

Answer:

yes

Explanation:

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6 0
3 years ago
What volume (in mL) of 0.250 M HCI would be
Nitella [24]

Answer: 1820 mL (to 3 sf)

Explanation:

The atomic mass of aluminum is 26.9815385 g/mol, so 4.10 g of aluminum is equal to 4.10/26.9815385 = 0.15195575300497 moles of Al.

From the coefficients of the equation, we know that for every 2 moles of aluminum consumed, 6 moles of HCl are consumed.

So, this means we need 0.15195575300497(6/2) = 0.45586725901491 moles of HCl.

Substituting into the molarity formula,

  • 0.250 = 0.45586725901491/(liters of HCl)
  • liters of HCl = 0.45586725901491/0.250
  • liters of HCl = 1.8234690360596 L = 1820 mL (to 3 sf)
4 0
2 years ago
A mixture containing nitrogen, hydrogen, and iodine established the following equilibrium at 400 °C:2NH3(g) + 3I2(g) ⇌ N2(g) + 6
miss Akunina [59]

Answer: The value of K_{c} for this reaction is 250000.

Explanation:

The given equation is as follows.

2NH_{3}(g) + 3I_{2}(g) \rightleftharpoons N_{2}(g) + 6HI(g)

N_{2}(g) + 3H_{2}(g) \rightleftharpoons 2NH_{3}(g); K_{c_{1}} = 0.50   ... (1)

H_{2}(g) + I_{2}(g) \rightleftharpoons 2HI(g); K_{c_{2}} = 50  ... (2)

To balance the atoms, multiply equation (2) by 3. Hence, the equation (2) can be re-written as follows.

3H_{2}(g) + 3I_{2}(g) \rightleftharpoons 6HI(g); K_{c_{2}} = (50)^{3}  ... (3)

Now, subtract equation (1) from equation (3). So, the equation formed will be as follows.

3I_{2} - N_{2} \rightleftharpoons 6HI - 2NH_{3}

This equation can also be re-written as follows.

3I_{2} + 2NH_{3} \rightleftharpoons N_{2} + 6HI

This equation is similar to the equilibrium equation given to us.

Therefore, during this subtraction the equation constants get divided as follows.

K^{'}_{c} = \frac{K_{c_{2}}}{K_{c_{1}}}\\= \frac{(50)^{3}}{0.50}\\= 250000

Thus, we can conclude that the value of K_{c} for this reaction is 250000.

6 0
2 years ago
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