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3 years ago

Please help me out with this question if you help me I will give you the brain thing and extra points. 8/9 image below.

Chemistry

2 answers:

Nataly [62]3 years ago

7 0

Answer:

the answer is most likely b, sorry if im wrong.

Explanation:

.....

castortr0y [4]3 years ago

6 0

B is the most logical anwser.

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Consider the following reaction: 2 NO(g) + 5 H2(g) → 2 NH3(g) + 2 H2O(g) Which set of solution maps would be needed to calculate

Leto [7]

Answer : The correct option is, (I) $gNO\rightarrow molNO\rightarrow molNH_3\rightarrow gNH_3$

Solution : Given,

Mass of NO = 45.8 g

Mass of $H_2$ = 12.4 g

Molar mass of NO = 30 g/mole

Molar mass of $H_2$ = 2 g/mole

Molar mass of $NH_3$ = 17 g/mole

First we have to calculate the moles of NO and $O_2$ .

$\text{ Moles of }NO=\frac{\text{ Mass of }NO}{\text{ Molar mass of }NO}=\frac{45.8g}{30g/mole}=1.53moles$

$\text{ Moles of }H_2=\frac{\text{ Mass of }H_2}{\text{ Molar mass of }H_2}=\frac{12.4g}{2g/mole}=6.20moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$2NO(g)+5H_2(g)\rightarrow 2NH_3(g)+2H_2O(g)$

From the balanced reaction we conclude that

As, 2 mole of $NO$ react with 5 mole of $H_2$

So, 1.53 moles of $NO$ react with $\frac{1.53}{2}\times 5=3.82$ moles of $H_2$

From this we conclude that, $H_2$ is an excess reagent because the given moles are greater than the required moles and $NO$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $NH_3$

From the reaction, we conclude that

As, 2 mole of $NO$ react to give 2 mole of $NH_3$

So, 1.53 mole of $NO$ react to give 1.53 mole of $NH_3$

Now we have to calculate the mass of $NH_3$

$\text{ Mass of }NH_3=\text{ Moles of }NH_3\times \text{ Molar mass of }NH_3$

$\text{ Mass of }NH_3=(1.53moles)\times (17g/mole)=26.0g$

Therefore, the maximum mass of $NH_3$ produced 26.0 grams.

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3 years ago

Cyclohexane (δh° = 936 kcal/mol ) and methylcyclopentane (δh° = 941 kcal/mol) have the same molecular formula but different stra

nadya68 [22]

The difference of the structures of the two isomers are shown in the picture. Generally, cyclic alkanes are much easier to break than straight-chained alkanes. When the molecules are cyclic, they are close to each other, thus lesser bond angles. Because they are closer, repulsion forces could be greater than attractive forces. That is why cyclohexane needs lesser energy of 936 kcal/mol compared to 941 kcal/mol because there is an additional straight-chained methyl substituent to break in methylcyclopentane.

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Kisachek [45]

Answer:

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