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muminat
2 years ago
6

According to the following reaction, how many moles of oxygen gas are necessary to form 0.408 moles carbon dioxide?

Chemistry
1 answer:
Neporo4naja [7]2 years ago
3 0

Answer:

2 molecules of oxygen are necessary

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Methane burns in oxygen to produce carbon dioxide and water. Which of the following represents
Brut [27]

Answer:

A

Explanation:

CH4+O2-CO2+ H20

that mean methane has burn in oxygen to produce CO2

8 0
3 years ago
What volume would be needed to prepare 375 mL of a .45 M CaCl2 using only a solution of 1.0 M CaCl2 and water?
Neporo4naja [7]

Answer:

168.75 ml

Explanation:

M1V1=M2V2

375ml*.45M=1M*V2

8 0
3 years ago
The heat of vaporization of 1-pentanol is 55.5 kJ/mol, and its entropy of vaporization is 148 J/K.mol. What is the approximate b
____ [38]

Answer:

Approximately 100 °C.

Explanation:

Hello,

In this case, since the entropy of vaporization is computed in terms of the heat of vaporization and the temperature as:

\Delta S_{vap}=\frac{\Delta H_{vap}}{T}

We can solve for the temperature as follows:

T=\frac{\Delta H_{vap}}{\Delta S_{vap}}

Thus, with the proper units, we obtain:

T=\frac{55500J/mol}{148J/(mol*K)} =375K\\\\T=102 \°C

Hence, answer is approximately 100 °C.

Best regards.

6 0
3 years ago
Describe a way to separate iron filings from sand.<br><br> Enter your answer in the space provided.
Lina20 [59]
Use the magnetic force of iron filings
5 0
3 years ago
Read 2 more answers
A solution is made by dissolving 3.35 g of fructose in 35.0 ml of water. What is the molality of fructose in the solution? Assum
ludmilkaskok [199]

Answer:

m = 0.531 molal

Explanation:

∴ m fructose = 3.35 g

∴ V water = 35.0 mL

∴ ρ H2O = 1 g/mL

  • molality = moles solute / Kg solvent

∴ Mw fructose = 180.16 g/mol

⇒ moles fructose = 3.35 g * ( mol / 180.16 g) = 0.0186 mol fructose

⇒ m H2O = 35.0 mL * ( 1 g/mL ) * ( Kg/1000g) = 0.035 Kg H2O

⇒ molality (m) = 0.0186 mol fructose / 0.035 Kg H2O

⇒ m = 0.531 molal

6 0
3 years ago
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