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ruslelena [56]
1 year ago
11

The cost of gas is $1.27 per liter. How much does a gallon of gas costs?

Physics
1 answer:
levacccp [35]1 year ago
7 0
It will be at least 30.00
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You use 8x binoculars were used on a warbler (14cm long) in a tree 18cm away. What angle (in degrees) does the image of the warb
mafiozo [28]

Answer:

The angle it subtend on the retina is  \theta_z = 0.44586^o    

Explanation:

From the question we are told that

     The length of the warbler is  L = 14cm = \frac{14}{100} = 0.14m

      The distance from the binoculars is    d = 18cm = \frac{18}{100} = 0.18m

        The magnification of the binoculars is  M =8

Without the 8 X binoculars the  angle made with the angular size of the object  is mathematically represented as

          \theta = \frac{L}{d}

        \theta  = \frac{0.14}{0.18}

           = 0.007778 rad

Now magnification can be represented mathematically as

         M = \frac{\theta _z}{\theta}

Where \theta_z is the angle the image of the warbler subtend on your retina when the   binoculars i.e the  binoculars zoom.

So

      \theta_z = M * \theta

=>    \theta_z =8 * 0.007778

            = 0.0622222224

Generally the conversion to degrees can be mathematically evaluated as

             \theta_z = 0.062222224 * (\frac{360 }{2 \pi rad} )

              \theta_z = 0.44586^o  

7 0
3 years ago
A baseball thrown from the outfield to home plate does not have which of the following types of energy while it's in the air? A.
posledela
The ball does not have D. Radiant energy.
7 0
2 years ago
Which of the following elements do living things have that volcanic rocks do not have?
jek_recluse [69]

Answer: silicon,or maybe none.

Explanation: I searched it up not really sure sorry

8 0
3 years ago
a flashlight has a resistance of 2.4 ohms. what voltage is applied by the batteries if the current in the circuit is 2.5A?
Mashcka [7]

E = I R

That means 

        Voltage = (current) x (resistance)

                     =   (2.5 A)  x  (2.4 ohms)

                     =       6 volts .


8 0
3 years ago
Read 2 more answers
A 7.00-kg object accelerates from rest to a final velocity in 55 seconds. If the magnitude of the
Len [333]

Answer:

The final velocity of the object is 330 m/s.

Explanation:

To solve this problem, we first must find the acceleration of the object.  We can do this using Newton's Second Law, given by the following equation:

F = ma

If we plug in the values that we are given in the problem, we get:

42 = 7 (a)

To solve for a, we simply divide both sides of the equation by 7.

42/7 = 7a/7

a = 6 m/s^2

Next, we should write out all of the information we have and what we are looking for.

a = 6 m/s^2

v1 = 0 m/s

t  = 55 s

v2 = ?

We can use a kinematic equation to solve this problem.  We should use:

v2 = v1 + at

If we plug in the values listed above, we should get:

v2 = 0 + (6)(55)

Next, we should solve the problem by performing the multiplication on the right side of the equation.

v2 = 330 m/s

Therefore, the final velocity reached by the object is 330 m/s.

Hope this helps!

7 0
3 years ago
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