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Igoryamba
3 years ago
6

In sublimation which state of matter is absent

Chemistry
2 answers:
tankabanditka [31]3 years ago
6 0

sublimation is the transition of a substance directly from the solid to the state without passing through the liquid state

Oliga [24]3 years ago
5 0
Liquid :) it goes directly from a solid to a gas. Have a nice day!
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What happens during jury deliberation in a criminal court case?<br>​
dlinn [17]

The following steps are usually followed: The foreperson tells the court security officer that a verdict has been reached. The judge calls everyone, including you, back into the courtroom, The clerk in the courtroom asks the foreperson for the verdict. The verdict is read into the record in open court.

4 0
3 years ago
each element is designated by its __________ which is usually from the first letters of the elements name
klemol [59]

Answer:

each element is designated by its <u>Chemical Symbol </u>which is usually from the first letters of the elements name

Explanation:

7 0
3 years ago
The volume (in L) that would be occupied by 5.00 mols of 02 at STP is
crimeas [40]

Answer : The volume of oxygen at STP is 112.0665 L

Solution : Given,

The number of moles of O_2 = 5 moles

At STP, the temperature is 273 K and pressure is 1 atm.

Using ideal gas law equation :

PV=nRT

where,

P = pressure of gas

V = volume of gas

n = the number of moles

T = temperature of gas

R = gas constant = 0.0821 L atm/mole K   (Given)

By rearranging the above ideal gas law equation, we get

V=\frac{nRT}{P}

Now put all the given values in this expression, we get the value of volume.

V=\frac{(5moles)\times (0.0821Latm/moleK)\times (273K)}{1atm}=112.0665L

Therefore, the volume of oxygen at STP is 112.0665 L

3 0
3 years ago
How many moles of CaCO3 are needed to react with 12.5 mol SO2​
grandymaker [24]
<h3><u>Answer;</u></h3>

= 12.5 Moles of CaSO3

<h3><u>Explanation</u>;</h3>

The reaction between CaCO3 and SO2 is given by the equation.

CaCO3(s) + SO2(g) → CaSO3(aq) + CO2(g)

The mole ratio between CaCO3 and SO2 is 1 : 1;

1 mole of CaCO3 reacts with 1 mole SO2 to form CaSO3 and CO2

Therefore;

<em>12.5 moles of SO2 will require 12.5 moles of CaSO3</em>

7 0
3 years ago
Instead of 6 M NaOH being added to the solution, 6 M HCl is added. How will this affect the test for the presence of ammonium io
Lera25 [3.4K]

Answer:

Ammonia gas(an alkaline gas with characteristics of choking or irritating smell) is not liberated when 6mole of HCl is added to the solution instead of 6mole of NaOH, to test for the presence of ammonium ion in the solution

Explanation:

As expected, when testing for ammonium ion in a solution (precisely ammonium salt solution), Sodium Hydroxide (NaOH) is required as the test reagent.

When NaOH is added to the solution, A gas with characteristics of choking or irritating smell is liberated.

This gas turn red litmus paper blue.

This liberated gas is an alkaline gas, which is confirmed as an ammonia gas(NH3).

If HCl is added instead of NaOH, the ammonia gas will not be liberated, which indicates that the test reagent used is wrong.

3 0
3 years ago
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