Question

The average speed of an oxygen molecule is 6.14 x 104 cm/sec at a certain temperature. What is the average speed of a CO2 molecule at the same temperature? (molar mass O2 = 31.9988; CO2 = 44.0098)

Answer 1

Answer:

the average speed of $V_{av} CO_2$ is 5.24 ×  104 cm/s

Explanation:

The computation of the average speed of a $CO_2$ is as follows:

$\sqrt{average} = \sqrt{\frac{8 RT}{\pi M} }$

where,

M = Molar mass

$V_{av} = \frac{\sqrt{1}}{M}$

Given that

$V_{av} \ of\ oxygen= 6.14 \times 10^4 cm/s$

The molar mass of oxygen i.e. (MO_2) = 31.9988 g/mol

And, the molar mass of CO_2 is  44.0098 g/mol

Now

$\frac{V_{av} CO_2}{V_{av} O_2} = \frac{\sqrt{M_{O2} }}{M_{CO2}}$

Now place these values to the above formula

$\frac{V_{av}CO_2}{6.14\times 104 cm/s} = \frac{\sqrt{31.9988} }{44.0098}$

So,

V_av CO_2 is 5.24 ×  104 cm/s

hence, the average speed of $V_{av} CO_2$ is 5.24 ×  104 cm/s