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Bond [772]
2 years ago
13

Can a average velocity be zero.Why? ​

Physics
1 answer:
marishachu [46]2 years ago
4 0

<u>Answer:</u>

Yes

<u>Explanation:</u>

Average velocity is the ratio of total displacement and time taken for that displacement:

average \space\ velocity = \frac{displacement}{time}

This means if displacement is zero, then average velocity will also be zero.

Displacement is zero when an object moves some distance in one direction, and then moves the same distance but in the opposite direction.

∴ As it is possible for displacement to be zero, it is also possible for average velocity to be zero.

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Determine the mass of fuel required for the expected energy consumption in the United States for the next 10 years:
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Answer:

(This will depend on the type of fuel, I will assume that the fuel is petrol)

First, let's find the expected energy consumption in the US for the next 10 years.

We know that in one year, a person consumes 3.5*10^11 joules.

There are 310,000,00 people on the US

Then the total consumption in one year is:

310,000,000*3.5*10^11 joules = 1.085*10^20 J

In 10 years the consumption is 10 times the consumption of a single year, then the expected energy consumption in the US for the next 10 years is:

10*1.085*10^20 J = 1.085*10^21 J

Now let's find the mass of fuel required.

We know that a liter of petrol has 31,536,000 joules of energy,

And a liter of petrol weights 0.75 kg

To find the number of liters of petrol that we need, we need to find the quotient between the expected energy consumption in the next 10 years and the energy of a single liter of petrol, this is:

N = (1.085*10^20 J)/(31,536,000 j) = 3.44*10^13

We will need  3.44*10^13 liters of petrol.

And the total mass of petrol will be:

M = 3.44*10^13*0.75 kg = 2.58*10^13 kg of fuel.

8 0
3 years ago
A high-jumper clears the bar and has a downward velocity of - 5.00 m/s just before landing on an air mattress and bouncing up at
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-- As she lands on the air mattress, her momentum is (m v)

Momentum = (60 kg) (5 m/s down) = 300 kg-m/s down

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Change = (60 kg-m/s up) - (300 kg-m/s down)

Magnitude of the change = <em>360 km-m/s </em>

The direction of the change is <em>up /\ </em>.

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Answer:

Explanation:

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