1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ololo11 [35]
2 years ago
15

Your friend has slipped and fallen. To help her up, you pull with a force F, as the drawing shows. The vertical component of thi

s force is 110 newtons (N), while the horizontal component is 122 N. Find (a) the magnitude of F and (b) the angle0.
Physics
1 answer:
sineoko [7]2 years ago
3 0

This question can be solved using the concept of the composition of the vector.

(a) The magnitude of F is b "164.27 N".

(b) The angle of the vector from horizontal is " ".

(a)

From the composition of the rectangular components of a vector, we know that the magnitude of the resultant vector is given by the following formula:

F = \sqrt{F_x^2+F_y^2}

where,

F_x = x-component of the force = 122 N

F_y = y-component of the force = 110 N

Therefore,

F = \sqrt{(122\ N)^2+(110\ N)^2}

<u>F = 164.27 N</u>

(b)

The angle of the vector is given by the following formula:

\theta = tan^{-1}(\frac{F_y}{F_x})\\\\\theta = tan^{-1}(\frac{110\ N}{122\ N})\\\\

<u>θ = 42.04°</u>

Learn more about the composition of vector here:

brainly.com/question/24313520?referrer=searchResults

You might be interested in
If 1495 j of heat is needed to raise the temperature of a 351 g sample of a metal from 55.0°c to 66.0°c, what is the specific he
forsale [732]
The amount of heat needed to increase the temperature of a substance by \Delta T is given by
Q= mC_s \Delta T
where m is the mass of the substance, Cs is its specific heat capacity and \Delta T is the increase of temperature.

If we re-arrange the formula, we get
C_s =  \frac{Q}{m \Delta T}
And if we plug the data of the problem into the equation, we can find the specific heat capacity of the substance:
C_s =  \frac{1495 J}{(351 g)(66.0^{\circ}C-55.0^{\circ}C)}=0.39 J/g^{\circ}C
6 0
3 years ago
Read 2 more answers
What principle explains why lifting heavy objects is easier using ramps?
Anna11 [10]
By using ramps you can easily push or pull the object up the ramp.
5 0
3 years ago
Read 2 more answers
Please help! Will give brainliest. 
I am Lyosha [343]

<span>The correct frequency when you tune a guitar is when you hear the right tune in your own hearing and standard. The measure frequency of a guitar string is when you measure the tune of the string correctly. This is not the same because manual tuning is affected by many factors.</span>

9 0
3 years ago
You can enter compound units that are combinations of other units that are multiplied together. to enter the ⋅ explicitly, type
alexdok [17]

Answer:

30 N \cdot m

Explanation:

The torque applied by a force can be calculated as

\tau = F d sin \theta

where

F is the magnitude of the force

d is the length of the arm

\theta is the angle between the direction of the force and the arm

In this problem, we have

F = 15 N

d = 2.0 m

\theta=90^{\circ}

Substituting into the equation, we find

\tau = (15)(2.0) sin 90^{\circ}=30 N \cdot m

7 0
3 years ago
A 500 kg sack of coal falls vertically onto a 2000 kg railroad flatcar which was initially moving horizontally at 3 m/s. no exte
Zinaida [17]

Since there are no external forces, including friction, act on the flatcar. after the sack rests on the flatcar, we would assume that momentum is conserved. This means that

total momentum of car before collision = total momentum of car after collision.

Recall,

momentum = mass x velocity

From the information given,

mass of car before collision = 2000

velocity of car before collision = 3

Thus,

total momentum of car before collision = 2000 x 3 = 6000

Also,

mass of sack = 500

mass of car and sack after collision = 500 + 2000 = 2500

velocity after collision = v

momentum after collision = 2500 x v = 2500v

Since momentum is conserved, then

6000 = 2500v

v = 6000/2500

v = 2.4

the speed of the flatcar is 2.4 m/s

6 0
1 year ago
Other questions:
  • A 5.0-μC charge is placed at the 0 cm mark of a meter stick and a -4.0 μC charge is placed at the 50 cm mark. At what point on a
    5·1 answer
  • A particle with a mass of 2.3 × 10-20 kg is oscillating with simple harmonic motion with a period of 3.0 × 10-5 s and a maximum
    9·1 answer
  • Three m^3 of air in a rigid, insulated container fitted with a paddle wheel is initially at 295 K, 200 kPa. The air receives 154
    12·1 answer
  • Do the conduction electrons in a copper wire act quantum mechanically or not? Roughly speaking, quantum mechanics comes in when
    7·1 answer
  • A man of mass 85 kg runs up a flight of stairs of height 4.6 m in a time period
    8·1 answer
  • Una persona en la tierra tiene una masa de 70[kg]. Calcule: a) Su fuerza peso en la tierra. b) Su fuerza peso en la luna (consid
    14·1 answer
  • A mason stretches a string between two points 70 ft apart on the same level with a tension of 20 lb at each end. If the string w
    11·1 answer
  • What is the general equation for a double-displacement reaction?
    6·1 answer
  • If a substance changes from a vapor to a liquid it ____ HELP FAST
    6·1 answer
  • PLS HELP ASAP I REALLY NEED HELP AND WILL GIVE BRAINLIEST &lt;2
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!