A 609 ml sample of naoh has a ph of 13.5292. if 594 ml of distilled water was added to the initial naoh solution, what would the

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2 years ago

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new ph of the solution be g

1 answer:

Delvig [45] · Answer 1 · 2023-11-10T19:45:34+03:00

The new pH of the solution after the addition of water would be 13.22.

<h3>Total volume of the solution</h3>

V(total) = 609 ml + 594 ml

V(total) = 1203 ml

<h3>Concentration of water </h3>

C = (594 ml)/(1203 ml)

C = 0.493

pOH = -log(0.493)

pOH = 0.31

New pH of the solution = 13.5292 - 0.31 = 13.22

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