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Anit [1.1K]
1 year ago
11

A 609 ml sample of naoh has a ph of 13.5292. if 594 ml of distilled water was added to the initial naoh solution, what would the

new ph of the solution be g
Chemistry
1 answer:
Delvig [45]1 year ago
8 0

The new pH of the solution after the addition of water would be 13.22.

<h3>Total volume of the solution</h3>

V(total) = 609 ml + 594 ml

V(total) = 1203 ml

<h3>Concentration of water </h3>

C = (594 ml)/(1203 ml)

C = 0.493

pOH = -log(0.493)

pOH = 0.31

New pH of the solution = 13.5292 - 0.31 = 13.22

Learn more about pH here: brainly.com/question/13557815

#SPJ1

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