A 609 ml sample of naoh has a ph of 13.5292. if 594 ml of distilled water was added to the initial naoh solution, what would the
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Answer:
<h3>Therefore, after long period of time 80kg of salt will remain in tank</h3>Explanation:
given amount of salt at time t is A(t)
initial amount of salt =300 gm =0.3kg
=>A(0)=0.3
rate of salt inflow =5*0.4= 2 kg/min
rate of salt out flow =5*A/(200)=A/40
rate of change of salt at time t , dA/dt= rate of salt inflow- ratew of salt outflow
integrating factor
integrating factor
multiply on both sides by
integrate on both sides
b)
after long period of time means t - > ∞
Answer:
Explanation:
F = ma