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4 years ago

8

A scientist studies an element that has seven electrons in its outer shell, is fairly toxic, and is highly reactive. To which gr

oup of the periodic table does this element belong

1 answer:

tangare [24]4 years ago

3 0

Answer:17

Explanation:cause i took the test

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What is the boiling point elevation constant, Kb, of diethyl ether if 38.2 g of the nonelectrolyte benzophenone, C6H5COC6H5, dis

kakasveta [241]

Answer: the boiling point elevation constant is $1.73^0C/m$

Explanation:

Elevation in boiling point is given by:

$\Delta T_b=i\times K_b\times m$

$\Delta T_b=T_b-T_b^0=$ = Elevation in boling point

i= vant hoff factor = 1 (for non electrolyte)

$K_b$ =boiling point constant = ?

m= molality

$\Delta T_b=i\times K_b\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}$

Weight of solvent (diethylether)= 330 g = 0.33 kg

Molar mass of solute (benzophenone)= 182 g/mol

Mass of solute (benzophenone) = 38.2 g

$(35.7-34.6)^0C=1\times K_b\times \frac{38.2g}{182g/mol\times 0.33kg}$

$K_b=1.73^0C/m$

Thus the boiling point elevation constant is $1.73^0C/m$

3 0

3 years ago

In 1860, Chemists could make which of the following statements about the known chemical elements?

LenKa [72]

Answer:

b. Some had similar properties

3 0

3 years ago

You're at the zoo and have a big red 1.80 L helium balloon. The barometric pressure today is 785 mmHg. Then you hear the roar of

fomenos

Answer: The volume of the balloon up there is 6.192 L.

Explanation:

Given: $V_{1}$ = 1.80 L, $P_{1}$ = 785 mm Hg (mm Hg = 0.00131579) = 1.032 atm

$P_{2}$ = 0.300 atm, $V_{2}$ = ?

Formula used to calculate volume is as follows.

$P_{1}V_{1} = P_{2}V_{2}$

Substitute the value into above formula as follows.

$P_{1}V_{1} = P_{2}V_{2}\\1.032 atm \times 1.80 L = 0.300 atm \times V_{2}\\V_{2} = 6.192 L$

Thus, we can conclude that the volume of the balloon up there is 6.192 L.

8 0

3 years ago

Two people are pushing on a shopping cart from opposite sides. When will the motion of

Darina [25.2K]

Answer:

The answer is B

7 0

3 years ago

A gas has a volume of 3.25 liters at 54 C and 231 kPa of pressure. At what temperature will the same gas take up 4.35 liters of

Firdavs [7]

Answer: 318 K

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 231 kPa

$P_2$ = final pressure of gas = 168 kPa

$V_1$ = initial volume of gas = 3.25 L

$V_2$ = final volume of gas = 4.35 L

$T_1$ = initial temperature of gas = $54^oC=273+54=327K$

$T_2$ = final temperature of gas = ?

Now put all the given values in the above equation, we get:

$\frac{231\times 3.25}{327}=\frac{168\times 4.35}{T_2}$

$T_2=318K$

At 318 K of temperature will the same gas take up 4.35 liters of space and have a pressure of 168 kPa

4 0

3 years ago