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Mariulka [41]
3 years ago
15

I will give the first person brainliest! please helppp

Chemistry
1 answer:
Murrr4er [49]3 years ago
7 0

okay so the  Answer is c

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What is Δn for the following equation in relating Kc to Kp?2 SO2(g) + O2(g) ↔ 2 SO3(g)23-2-11
san4es73 [151]

Answer:

-1

Explanation:

The relation between Kp and Kc is given below:

K_p= K_c\times (RT)^{\Delta n}

Where,  

Kp is the pressure equilibrium constant

Kc is the molar equilibrium constant

R is gas constant

T is the temperature in Kelvins

Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)

For the first equilibrium reaction:

2SO_2_{(g)}+O_2_{(g)}\rightleftharpoons2SO_3_{(g)}

<u>Δn = (2)-(2+1) = -1  </u>

Thus, Kp is:

K_p=  K_c\times (RT)^{-1}

4 0
3 years ago
Can anyone help me with nuclear chemistry???
Shtirlitz [24]

Yes, I am happy to help you, but if you know that just asking this, people earn points practically free.

8 0
4 years ago
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Convert the pressure 525.4 torr to kPa.
Virty [35]

Answer:

A. 70.0 kpa

Explanation:

Given

Pressure = 525.4 torr

Required

Convert to kPa

From standard unit of conversion;

1\ torr = 0.133\ kPa

Multiply both sides by 525.4

525.4 * 1\ torr = 525.4 * 0.133\ kpa

525.4\ torr = 70.047572\ kpa

525.4\ torr = 70.0\ kpa <em>(Approximated)</em>

<em>From the list of given options, option A is the closest answer after 525.4 torr is converted to its kpa equivalent</em>

8 0
3 years ago
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A 100.0 ml sample of 0.18 m hclo4 is titrated with 0.27 m lioh. determine the ph of the solution after the addition of 100.0 ml
Naddika [18.5K]
(I think you have a mistake in your question as the addition is 30mL, not 100mL)
when PH = - ㏒[H+]
and here we have HClO4 is the strong acid
So PH = - ㏒[HClO4]

moles of HClO4 = 0.1 L *0.18 m = 0.018 M
moles of LiOH = 0.03 L * 0.27 m = 0.0081 M
when the total volume = 0.1L + 0.03L =  0.13 L
∴ [HClO4] = (0.018-0.0081)/0.13 L
                 = 0.076 M
PH = -㏒ 0.076
      = 1.12
5 0
4 years ago
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Gold (au) goes from an oxidation number of +3 to 0 in the reaction below. 2Au3+ + 6I- ---&gt; 2Au + 3I2. what describes the Au3+
mamaluj [8]
In a reduction-oxidation or better known as REDOX reaction, the substance that reduces the oxidation state is known as the substance that is REDUCED. It serves as the oxidizing agent. Thus, Au3+  in this number is considered as the oxidizing agent. 
7 0
3 years ago
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