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dalvyx [7]
3 years ago
11

A solution containing less than the equilibrium amount is called ________. a solution containing less than the equilibrium amoun

t is called ________. a dilute solution an unsaturated solution a saturated solution a supersaturated solution a concentrated solution
Chemistry
2 answers:
IrinaK [193]3 years ago
8 0

Answer: unsaturated solution.

Explanation:

Saturation can be defined as the the degree in which solute is dissolved. There are three main types of saturation, they are; supersaturated solution, saturated solution and unsaturated solution.

Let us take a quick look at the three types below.

(1). Supersaturated solution: a supersaturated solution is that solution containing more undissolved solids than the saturated solution. In other words, supersaturated solution is a solution containing containing more than the equilibrium amount in a solute more than the saturated solution. Leaving undissolved solute at the buttom.

(2). Saturated solution: saturated solution is that solution that dissolves solute to its maximum level where it can dissolve no more. Here, the undissolved solute at the buttom is not as much as the one in the Supersaturated solution.

(3). Unsaturated solution: is a solution A solution containing less than the equilibrium amount of solute.

Alex787 [66]3 years ago
6 0
<span>I believe it is an unsaturated solution.</span>
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B. For the following questions, use the reaction NO2(g) N2(g) + O2(g), with ΔH = –33.1 kJ/mol and ΔS= 63.02 J/(mol·K).
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Answer:

I. Kindly, see the attached image.

II. The reaction is exothermic.

III. - 51.88 kJ/mol.

IV. The reaction is spontaneous.

Explanation:

I. Draw a possible potential energy diagram of the reaction. Label the enthalpy of the reaction.

  • Since the sign of ΔH is negative, the reaction is exothermic reaction.

In an exothermic reaction, the energy of the reactants is higher than that of the products.

<u><em>Kindly see the attached image to show you the potential energy diagram of the reaction.</em></u>

     

<em>II. Is the reaction endothermic or exothermic? Explain your answer.</em>

  • The reaction is exothermic reaction.
  • The sign of ΔH indicates wither the reaction is endothermic or exothermic one:

If the sign is positive, the reaction is endothermic.

If the sign is negative, the reaction is exothermic.

Herein, <em>ΔH = - 33.1 kJ/mol, </em>so the reaction is exothermic.

<em>III. What is the Gibbs free energy of the reaction at 25°C? </em>

∵ ΔG = ΔH - TΔS.

Where, ΔG is the Gibbs free energy change (J/mol).

ΔH is the enthalpy change (ΔH = - 33.1 kJ/mol).

T is the temperature (T = 25°C + 273 = 298 K).

ΔS is the entorpy change (ΔS = 63.02 J/mol.K = 0.06302 J/mol.K).

<em>∴ ΔG = ΔH - TΔS</em> = (- 33.1 kJ/mol) - (298 K)(0.06302 J/mol.K) = <em>- 51.88 kJ/mol.</em>

IV. Is the reaction spontaneous or nonspontaneous at 25°C?

The sign of ΔG indicates the spontaneity of the reaction:

If ΔG < 0, the reaction is spontaneous.

If ΔG = 0, the reaction is at equilibrium.

If ΔG > 0, the reaction is nonspontaneous.

Herein, <em>ΔG = - 51.88 kJ/mol, </em>so the reaction is spontaneous.

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5. What is the final "Celsius" temperature if 2.40 L of gas at 30.5 C is cooled until the volume reaches 1.00 L at constant pres
slega [8]

Answer:

Final temperature of the gas = -146.63 °C

Explanation:

At constant pressure, volume and temperature of the gases are related as:

\frac{V_1}{T_1}=\frac{V_2}{T_2}

Where,

V1 = Initial volume = 1.00 L

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T1 = Initial temperature = 30.5 °C = 30.5 + 273.15 = 303.65 K

Now, substitute the values in the above equation,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

\frac{2.40\;L}{303.65}=\frac{1.00\;L}{T_2}

T_2=\frac{1.00\times 303.65}{2.40}

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T(K) = T( °C) + 273.15  

T( °C) = T(K) - 273.15

          = 126.52 - 273.15 = -146.63 °C

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