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dalvyx [7]
3 years ago
11

A solution containing less than the equilibrium amount is called ________. a solution containing less than the equilibrium amoun

t is called ________. a dilute solution an unsaturated solution a saturated solution a supersaturated solution a concentrated solution
Chemistry
2 answers:
IrinaK [193]3 years ago
8 0

Answer: unsaturated solution.

Explanation:

Saturation can be defined as the the degree in which solute is dissolved. There are three main types of saturation, they are; supersaturated solution, saturated solution and unsaturated solution.

Let us take a quick look at the three types below.

(1). Supersaturated solution: a supersaturated solution is that solution containing more undissolved solids than the saturated solution. In other words, supersaturated solution is a solution containing containing more than the equilibrium amount in a solute more than the saturated solution. Leaving undissolved solute at the buttom.

(2). Saturated solution: saturated solution is that solution that dissolves solute to its maximum level where it can dissolve no more. Here, the undissolved solute at the buttom is not as much as the one in the Supersaturated solution.

(3). Unsaturated solution: is a solution A solution containing less than the equilibrium amount of solute.

Alex787 [66]3 years ago
6 0
<span>I believe it is an unsaturated solution.</span>
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A chemistry student must write down in her lab notebook the concentration of a solution of sodium hydroxide. The concentration o
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Answer:

The concentration the student should write down in her lab is 2.2 mol/L

Explanation:

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S: 32.065 u

O: 15.999 u

Molar mass of sodium thiosulfate, Na2S2O3 = (2*22.989 + 2*32.065 + 3*15.999) g/mol = 158.105 g/mol.

Mass of Na2S2O3 taken = (19.440 - 2.2) g = 17.240 g.

For mole(s) of Na2S2O3 = (mass taken)/(molar mass)

= (17.240 g)/(158.105 g/mol) = 0.1090 mole.

Volume of the solution = 50.29 mL = (50.29 mL)*(1 L)/(1000 mL)

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To find the molar concentration of the sodium thiosulfate solution prepared we use the formula:

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= (0.1090 mole)/(0.05029 L)

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