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dalvyx [7]
3 years ago
11

A solution containing less than the equilibrium amount is called ________. a solution containing less than the equilibrium amoun

t is called ________. a dilute solution an unsaturated solution a saturated solution a supersaturated solution a concentrated solution
Chemistry
2 answers:
IrinaK [193]3 years ago
8 0

Answer: unsaturated solution.

Explanation:

Saturation can be defined as the the degree in which solute is dissolved. There are three main types of saturation, they are; supersaturated solution, saturated solution and unsaturated solution.

Let us take a quick look at the three types below.

(1). Supersaturated solution: a supersaturated solution is that solution containing more undissolved solids than the saturated solution. In other words, supersaturated solution is a solution containing containing more than the equilibrium amount in a solute more than the saturated solution. Leaving undissolved solute at the buttom.

(2). Saturated solution: saturated solution is that solution that dissolves solute to its maximum level where it can dissolve no more. Here, the undissolved solute at the buttom is not as much as the one in the Supersaturated solution.

(3). Unsaturated solution: is a solution A solution containing less than the equilibrium amount of solute.

Alex787 [66]3 years ago
6 0
<span>I believe it is an unsaturated solution.</span>
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Answer:

21.3 g of CaCl₂ are produced in this reaction

Explanation:

Reaction is this:

CaCO₃ +  2HCl → CaCl₂ + H₂CO₃

Molar mass salt : 100.08 g/m

Molar mass acid: 36.45 g/m

We have 28 g / 100.08 g/m = 0.279 moles of CaCO₃

We have 14 g / 36.45 g/m = 0.384 moles of HCl

Ratio is 1:2, so 0.279 moles of salt will need the double of moles of acid.

0.279 . 2 = 0.558 moles of acid needed. (I have only 0.384 moles, so the acid is the limiting reactant)

0.384 moles of HCl produce the half of moles of CaCl₂ (This ratio is 1:2) --> 0.192 moles

Molar mass of CaCl₂ = 110.98 g/m

Mol . molar mass = mass → 0.192 m . 110.98 g/m = 21.3 g

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37.2 liters of a gas has a pressure of 362.43 kPa at 46.5 °C. If the pressure increases to
Nataliya [291]

Answer:

Option A. 25.7 L.

Explanation:

Step 1:

Data obtained from the question. This include the following:

Initial volume (V1) = 37.2 L

Initial pressure (P1) = 362.43 kPa

Initial temperature (T1) = 46.5 °C

Final pressure (P2) = 693.9 kPa

Final temperature (T2) = 149.2 °C

Final volume (V2) =.?

Step 2:

Conversion of celsius temperature to Kelvin temperature.

This can be achieved as shown below:

Temperature (K) = Temperature (°C) + 273

T (K) = T (°C) + 273

Initial temperature (T1) = 46.5 °C

Initial temperature (T1) = 46.5 °C + 273 = 319.5 K.

Final temperature (T2) = 149.2 °C

Final temperature (T2) = 149.2 °C + 273 = 422.2 K.

Step 3:

Determination of the new volume.

This can be obtained by using the general gas equation as shown below:

Initial volume (V1) = 37.2 L

Initial pressure (P1) = 362.43 kPa

Initial temperature (T1) = 319.5 K

Final pressure (P2) = 693.9 kPa

Final temperature (T2) = 422.2 K

Final volume (V2) =.?

P1V1/T1 = P2V2/T2

362.43×37.2/319.5 = 693.9 × V2/422.2

Cross multiply

319.5×693.9×V2 = 362.43×37.2×422.2

Divide both side by 319.5 × 693.9

V2 = (362.43×37.2×422.2)/(319.5×693.9)

V2 = 25.7 L

Therefore, the new volume is 25.7 L.

8 0
4 years ago
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