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Mandarinka [93]
2 years ago
7

A sample of helium gas inside a closed but flexible container occupies a volume of 355mL at 23°C. If the pressure is held consta

nt, to what temperature must the He be raised to cause the container to expand to a final volume of 1.50 L?
Chemistry
1 answer:
guapka [62]2 years ago
6 0

Answer:

978.19° C

Explanation:

P1V1/T1 =P2V2/T2     Since the pressure is constant, this can be written as

V1/T1 = V2/T2      RE-ARRANGE TO

V2 *  T1/V1   = T2       Note:  T must be in Kelvin!!

1.5 L  *  (273.15 + 23)  / (.355 L ) = T2 = 1251.338 K  =978.19 C

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Answer:

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Explanation:

2Na3PO4(aq) + 2CoCl2(aq) → 2Co3(PO4)2(s) + 6NaCl(aq)

The question ask us to list the number of the kind of atom found on the left side(reactant) of the chemical equation. The question also reiterated that the order of the numbers should be the same as the order of the elements on the left side of the equation.

The type of atoms found on the left side of the equation are as follows;

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The equation on the left hand side have sodium atom, phosphorus atom, oxygen atom, cobalt atom and chlorine atom.

Note: The given equation is not balanced but it can be balanced as follows;

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The balanced equation have the following number of atom on the left side:

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Consider the combustion of octane (C8H18)
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The balanced equation for the above reaction is as follows;
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number of CO₂ moles formed - 13.45 mol
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