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____ [38]
4 years ago
14

1.73 lbs of salt in 3.70 lbs of water what is the percentage of salt in the mixture

Chemistry
1 answer:
Delicious77 [7]4 years ago
3 0
1.73 ÷ 3.7 × 100 = 46.75675675675676

Answer: There is 46.76% of salt in the mixture.
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3) A child has a toy balloon with a volume of 1.8 liters. The temperature of the balloon when it was filled was 22° C and the pr
mestny [16]

This is a combined gas law problem, according to which

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

where P is the pressure of the gas, V is the volume of the gas, and T is the temperature of the gas, and the subscripts 1 and 2 correspond to the initial and final conditions of the gas. In this problem, we are given the initial pressure, volume, and temperature of the gas in the balloon:

P₁ = 1.0 atm

V₁ = 1.8 L

T₁ = 295.15 K (K = °C + 273.15).

Moreover, we are given the final pressure and temperature of the gas in the balloon.

P₂ = 0.86 atm

T₂ = 281.15 K.

What we want to find is the final volume, V₂, which we can obtain by rearranging the combined gas equation to solve for V₂:

V_2=\frac{P_1V_1T_2}{T_1P_2} = \frac{(1.0 \text{ atm})(1.8 \text{ L})(281.15 \text{ K})}{(295.15 \text{ K})(0.86 \text{ atm})} \\ V_2 = 1.99 \text{ L}

This answer has three significant figures. However, the question as written would warrant an answer that comprises one significant figure (as 8 °C has only one sig fig). In that case, the answer would be 2 L. If the answer is to be given to two significant figures, the volume would then be 2.0 L.

8 0
3 years ago
A gas in a rigid container has a pressure of 3.5 atm at 200. k calculate the pressure at 273 k
rusak2 [61]

Answer:

4.78atm

Explanation:

From the question, we obtained the following:

P1 (initial pressure) = 3.5 atm

T1 (initial temperature) = 200K

T2 (final temperature) = 273K

P2 (final pressure) =?

Using P1/T1 = P2/T2, the final pressure can be obtained as shown below:

P1/T1 = P2/T2

3.5/200 = P2/273

Cross multiply to express in linear form as shown below:

200 x P2 = 3.5 x 273

Divide both side by 200

P2 = (3.5 x 273)/200

P2 = 4.78atm

Therefore, the pressure at 273K is 4.78atm

6 0
3 years ago
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