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____ [38]
4 years ago
14

1.73 lbs of salt in 3.70 lbs of water what is the percentage of salt in the mixture

Chemistry
1 answer:
Delicious77 [7]4 years ago
3 0
1.73 ÷ 3.7 × 100 = 46.75675675675676

Answer: There is 46.76% of salt in the mixture.
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Correct way for calculating atomic mass
kolezko [41]

Answer:

mass number = protons + neutrons.

Explanation:

Together, the number of protons and the number of neutrons determine an element's mass number: mass number = protons + neutrons. If you want to calculate how many neutrons an atom has, you can simply subtract the number of protons, or atomic number, from the mass number.

5 0
2 years ago
A 0.875-g sample of anthracite coal was burned in a bomb calorimeter. The temperature rose from 22.50 to 23.80°C. The heat capac
kherson [118]

Answer:

a) 26.65 kJ was the heat evolved by the reaction.

b) 3.046\times 10^7 kJ is the energy released on burning 1 metric ton  of this type of coal

Explanation:

Heat capacity of the calorimeter = C = 20.5 kJ/°C

Initial temperature of the calorimeter,T_1 = 22.50°C

Final temperature of the calorimeter,T_2 = 23.80°C

The heat evolved by the reaction = Q

Q=C(T_2-T_1)

Q=20.5 kJ/^oC\times (23.80^oC-22.50^oC)

Q=26.65 kJ

26.65 kJ was the heat evolved by the reaction.

0.875 g sample of anthracite coal was burned in a bomb calorimeter

0.875 g sample of anthracite coal gives 26.65 kJ of heat.

1 metric ton= 1000 kg

1000 kg = 1000 × 1000 g = 1,000,000 (1 kg =1000 g)

Then burning 1,000,000 g coal will give:

=\frac{26.65 kJ }{0.875}\times 1,000,000 g=3.046\times 10^7 kJ

3.046\times 10^7 kJ is the energy released on burning 1 metric ton  of this type of coal

8 0
3 years ago
Which pair of elements is most likely to form an ionic bond?
Sphinxa [80]
C.
Ionic bonds are formed between metal atoms, potassium in this case, and non-metal atoms, iodine in this case.
7 0
3 years ago
What is the mass of 5.80x10^23 atoms of silver
Natasha_Volkova [10]

Answer:

<h3>5.80000000E+ 46...</h3>

follow me and mark me brainliest

6 0
3 years ago
Silver sulfate (Ag2SO4) is slightly soluble in water and it partly dissolves at the equilibrium according to the following balan
statuscvo [17]

Answer:

a) S = 0.0152 mol/L

b) S' = 4.734 g/L

Explanation:

  • Ag2SO4 ↔ 2Ag+  +  SO42-

           S                2S            S...............in the equilibrium

  • Ksp = 1.4 E-5 = [ Ag+ ]² * [ SO42-]

a) molar solubility:

⇒ Ksp = ( 2S) ² * S = 1.4 E-5

⇒ 4S² * S = 1.4 E-5

⇒ S = ∛ ( 1.4 E-5 / 4 )

⇒ S = 0.0152 mol/L

b) solubility ( S' ) in grams per liter:

∴ Mw Ag2SO4 = 311.799 g/mol

⇒ S' = 0.0152 mol/L * ( 311.799 g/mol )

⇒ S' = 4.734 g/L

3 0
3 years ago
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