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3 years ago

What is the variable for the equilibrium constant?

Chemistry

2 answers:

sladkih [1.3K]3 years ago

5 0

THE CONSTANT OF A VARIABLE FOR THE EQUALIRBIN CONSTANT

Drupady [299]3 years ago

4 0

Answer:

The constant can be calculated using the ratio of products to reactants when the equation has reached equilibrium. The equilibrium constant is often represented by the variable Keq, which is defined by the equilibrium constant expression

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The Ksp can be used to find the concentration of hydroxide ions, and thus determine the pH given a concentration of of aluminum.

Anton [14]

Answer:

3.9.

Explanation:

(Molar mass of 342.15 g/mol).

The first thing to do in this question is to coverts our units. We are given 6.70 lb = 453.592 × 6.70 lb = 3039.0664 g of aluminum sulfate.

2050 gallons of water = 2050 × 3.785 = 7759.25 Litres.

After this we will now look for the Concentration aluminum sulfate using the formula below:

Concentration = number of moles ÷ volume. ------------------------------------(1).

Recall; Number of moles = 3039.0664/ 342.15 = 8.8823 moles. The volume = 2050 gallons = 7759.25 Litres.

Therefore, slotting in the values of of number of moles and volume into the equation (1) above, we have;

Concentration= 8.8823 moles/ 7759.25 Litres. = 0.001145 M.

The next equation we are going to make use of today is that of the solubilty product that is;

Ksp = (Al^3+) (OH^-)^3.

So, we have the ksp = 1.3 × 10^-33 and the value of (Al^3+)= 0.001145 M.

Hence, making (OH^-) the subject of the formula;

(OH^-) = ( 1.3 × 10^-33 / 0.001145)^1/3.

(OH^-) = 8 × 10^-11 M.

Hence, pOH = - log (OH^-)

pOH = - log (8 × 10^-11).

pOH = 10.1

Therefore, the values of pH is; 1

pH + pOH = 14.

pH = 14 - 10.1 = 3.9.

3 0

3 years ago

Gold is currently trading at very high price. Suppose that gold is selling for around $1860/ounce. How

Ugo [173]

Answer:

The answer is "3.81041978"

Explanation:

$\to 1 \ OZ= 28.349523125 \ grams\\\\$

$=28.349523125\times {1000} \ miligrams\\\\= 28349. 5231 \ miligrams\\$

In 1860 $= 28349.5231 \ miligrams\\$

$\to In \$ \ 1 = \frac{28349.5231}{1860} \ \ miligrams\\$

$= 15.2416791 \ miligrams$

$\ In \ 1 \ quarter = \$ \ 0.25$

$\to \$ \ 0.25 = 15.2416791 \times 0.25 \ miligrams\\$

$= 3.81041978$

3 0

3 years ago

How many meters are in a kilometer.

Anika [276]

Answer:

1,000 meters in 1 kilometer

Explanation:

4 0

3 years ago

What is Keq for the reaction N₂ + 3H2 = 2NH3 if the equilibrium

hram777 [196]

The Keq for the reaction N₂ + 3H2 = 2NH3 if the equilibrium concentrations are Keq = 1.5. The correct option is D.

Keq is the ratio of the concentration of reactant to the concentration of the product.

The balanced equation is

N₂ + 3H₂ = 2NH₃

The equilibrium constant is $\rm \dfrac{[NH_3]^2}{[N_2]\; [H_2]^3}$

The given concentrations of the compounds have been:

Ammonia = 3 M

Nitrogen = 1 M

Hydrogen = 2 M

$\rm \dfrac{9}{1\times 8} = 1.5$

Thus, the correct option is D. Keq = 1.5.

Learn more about Keq

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3 0

2 years ago

What information does the third quantum number of an electron give? A. The direction the electron in spinning B. The energy leve

Juli2301 [7.4K]

The information that the third quantum number of an electron gives is the direction the electron in spinning. That is option A.

<h3>What are quantum numbers?</h3>

Quantum number are those numbers that are used to specify the properties of the atomic orbitals and the electrons in those orbitals.

The types of quantum numbers include the following:

principal,

azimuthal,

magnetic, and spin.

The third quantum number is shows the direction of the electron while spinning through specifying its angular momentum.

Learn more about orbitals here:

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4 0

2 years ago