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hoa [83]
3 years ago
5

Why is deuterium oxide called “heavy water”?

Chemistry
2 answers:
kompoz [17]3 years ago
6 0

Answer:

it is going to B because the hydrogen and some antonyms are heavier than others and that makes it heavy water basically

Explanation:

hope that helps I also looked it up and I've also been learning the same thing so I have my notes that I can study

konstantin123 [22]3 years ago
3 0

Answer:

a) su as tomos de oxigeno son mas pesdos que lo otros

Explanation:

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Turgor, an internal stimulus, refers to —
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Answer:

which has a lower freeging point oxgyen or ethanol

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3 years ago
Please help me !!!!
just olya [345]

Answer:

12, 28, 16

Explanation:

If we are trying to find mass, neutrons are our guy. 28 "mass points" means 28 neutrons. Each neutron is one point

We know there are 12 protons and electrons if we look at a table of elements, the number in the top-left is always the number of protons and we can subtract mass from the protons to get our electrons

3 0
3 years ago
The reaction converting glycerol to glycerol-3-phosphate can be represented as: glycerol + hpo42− ⟶ glycerol-3-phosphate + h2o.
Volgvan

Answer;

Yes; this reaction be spontaneous if coupled with the hydrolysis of ATP.

Explanation;

The reaction converting glycerol to glycerol-3-phosphate (energetically unfavorable) can be coupled with the conversion of ATP to ADP (energetically favorable):

Glycerol + HPO42 ⟶glycerol-3-phosphate+H2O

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6 0
3 years ago
Read 2 more answers
Suppose a 0.025M aqueous solution of sulfuric acid (H2SO4) is prepared. Calculate the equilibrium molarity of SO4−2. You'll find
FromTheMoon [43]

<u>Answer:</u> The concentration of SO_4^{2-} at equilibrium is 0.00608 M

<u>Explanation:</u>

As, sulfuric acid is a strong acid. So, its first dissociation will easily be done as the first dissociation constant is higher than the second dissociation constant.

In the second dissociation, the ions will remain in equilibrium.

We are given:

Concentration of sulfuric acid = 0.025 M

Equation for the first dissociation of sulfuric acid:

       H_2SO_4(aq.)\rightarrow H^+(aq.)+HSO_4^-(aq.)

            0.025          0.025       0.025

Equation for the second dissociation of sulfuric acid:

                    HSO_4^-(aq.)\rightarrow H^+(aq.)+SO_4^{2-}(aq.)

<u>Initial:</u>            0.025            0.025      

<u>At eqllm:</u>      0.025-x          0.025+x        x

The expression of second equilibrium constant equation follows:

Ka_2=\frac{[H^+][SO_4^{2-}]}{[HSO_4^-]}

We know that:

Ka_2\text{ for }H_2SO_4=0.01

Putting values in above equation, we get:

0.01=\frac{(0.025+x)\times x}{(0.025-x)}\\\\x=-0.0411,0.00608

Neglecting the negative value of 'x', because concentration cannot be negative.

So, equilibrium concentration of sulfate ion = x = 0.00608 M

Hence, the concentration of SO_4^{2-} at equilibrium is 0.00608 M

4 0
3 years ago
Which of the following is the smallest volume?
jok3333 [9.3K]
The     (B) answer     (B)     is    (B)               (B)           (B)


6 0
3 years ago
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