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2 years ago

Why is deuterium oxide called “heavy water”?

Chemistry

2 answers:

kompoz [17]2 years ago

6 0

Answer:

it is going to B because the hydrogen and some antonyms are heavier than others and that makes it heavy water basically

Explanation:

hope that helps I also looked it up and I've also been learning the same thing so I have my notes that I can study

konstantin123 [22]2 years ago

3 0

Answer:

a) su as tomos de oxigeno son mas pesdos que lo otros

Explanation:

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Fine the volume in dm³ and in Ml of a 0.505 mol/dm of NaCH required to react with 40Ml of 0.505 molar concentration of H2SO4

dedylja [7]

watch u know bout rolling down in the deep...

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2 years ago

In the graphic, 195 represents the _______.

Marrrta [24]

Answer:

ITS ANSWER IS

OPTION B. ATOMIC NUMBER

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5 0

2 years ago

A weather balloon is inflated to a volume of 27.9L at a pressure of 732mmHg and a temperature of 30.1?C. The balloon rises in th

masya89 [10]

Answer:

45.4 L

Explanation:

Using Ideal gas equation for same mole of gas as

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

Given ,

V₁ = 27.9 L

V₂ = ?

P₁ = 732 mmHg

P₂ = 385 mmHg

T₁ = 30.1 ºC

T₂ = -13.6 ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (30.1 + 273.15) K = 303.25 K

T₂ = (-13.6 + 273.15) K = 259.55 K

Using above equation as:

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

$\frac{{732}\times {27.9}}{303.25}=\frac{{385}\times {V_2}}{259.55}$

$\frac{385V_2}{259.55}=\frac{20422.8}{303.25}$

$148225V_2=6729708.26018$

Solving for V₂ , we get:

7 0

3 years ago

When a cold pack is used, ammonium chloride mixes with water and energy is absorbed from the water to reduce the temperature of

Leto [7]

I think the answer is Endothermic. Since the question says "absorbs," endo means to "go in" sort of and exo means to exit.

exo = exit
endo = enter
(A trick my teacher taught us)

Sorry if I'm wrong, hope I helped. :)

7 0

2 years ago

Read 2 more answers

Calculate the standard potential, e°, for this reaction from its equilibrium constant at 298 k. 6.47 x 10^5

Elina [12.6K]

The working equation for this is written below:

E° = 0.0592logK/n

So, we have to know the value of n first which represents the number of moles electron in the reaction. We cannot answer this because we are not given with the reaction. However, just suppose the reaction is:

Cu⁺ + 2e⁻ --> Cu

Then, n=2. Continuing,

E° = 0.0592log(6.47×10⁵)/2 =<em> 0.172 V</em>

4 0

2 years ago