Volume of O2 = 22.4 x moles of O2
= 22.4 x 1.2
= 26.88L
Answer:
USe this Nernst equation and find your required answer
Explanation:
E = E0 - [0.0592 /n ] log [Cd+2]/[Co2+]
Wher Eo is +0.120 V
[Cd+2] =0.1
[Co2+] = 0.001
n is number of electons transfered int he process and in your case it is = 2
E= 0.120- 0.0296 * log 100
= ........ V
Answer:
Explanation:
<u>1) Arrhenius equation</u>
Arrhenius equation shows the relation between activation energy, temperature, and the equilibrium constant.
This is the equation:
Where:
- K is the equilibrium constant,
- A is the frequency factor,
- Ea is the activation energy (in J/mol),
- T is the temperature in kelvins (K), and
- R is the universal constant.
<u></u>
<u>2) Substitute, using the right units, and compute:</u>
- A = 4.20 × 10¹² (dimensionless)
- Ea = 67.0 kJ/mol = 67,000 J/mol
- T = 24.0°C = 24.0 + 273.15 K = 297.15 K
- R = 8.314 J/K mol
D, because isotopes all have the same atomic number but different number of neutrons
Answer:
Cheese will be limiting reactant.
Explanation:
In given question it is stated that two slices of breads are required for one sandwich. The total bread slices available are 52. we divide the 52 by 2 to determine the number of sandwich which could made from 52 slices.
52/2 = 26
26 sandwich could be made from 52 bread slices.
The amount of cheese required for one sandwich is 3 slices. The available slices of cheese are 69.
69/3 = 23
we can see that only 23 set of slices of cheese are available while bread slices are available for 26 sandwiches. so we can make only 23 sandwiches from given quantity of ingredients. The 6 slices or 3 set of bread will left, because cheese is limited.
