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Stolb23 [73]
2 years ago
14

The energy produced by the snack in an experiment is calculated to be 41,800 J/g. What is the energy of the snack in Calories/

Chemistry
1 answer:
Goryan [66]2 years ago
5 0

The energy of the snack in calories per gram is 9983.3 Calories/gram.

<h3>What is the energy of a snack?</h3>

The energy that is contained in a snack is obtained from a calorimeter when the snack is burnt in a calorimeter. The mass of the snack that is burnt is measured in terms of energy output of the calorimeter.

If  1 calorie = 4.18J

x calorie = 41,800 J

x = 41,800 J * 1 calorie/4.18J

x = 9983.3 Calories/gram

Learn ore about energy in food:brainly.com/question/9602807

#SPJ1

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Why does electronegativity increase as you move from left to right across
Katen [24]

Answer: increasing number of protons increases the positive charge of the nucleus.

Explanation: because as the electronegativity moves from left to right on the periodic table the protons do increase to make it into a positive charge.

7 0
3 years ago
WILL MARK BRAINLIEST!! URGENT CORRECT ANSWERS NEEDED
atroni [7]
I hope this helps you;);

6 0
3 years ago
A sample of PCl5(g) was placed in an otherwise empty flask at an initial pressure of 0.500 atm and a temperature above 500 K. Ov
tia_tia [17]

Answer:

Kp = 0.81666

Explanation:

Pressure of PCl₅ = 0.500 atm

Considering the ICE table for the equilibrium as:

                     PCl₅ (g)      ⇔          PCl₃ (g) +       Cl₂ (g)

t = o               0.500

t = eq                -x                             x                      x

--------------------------------------------- --------------------------

Moles at eq: 0.500-x                       x                      x

       

Given the pressure of PCl₅ at equilibrium = 0.150 atm

Thus, 0.500 - x = 0.150

x = 0.350 atm

The expression for the equilibrium constant is:

K_p=\frac {P_{PCl_3}P_{[Cl_2}}{P_{PCl_5}}  

So,

K_p=\frac{x^2}{0.500-x}  

x = 0.350 atm

Thus,

K_p=\frac{{0.350}^2}{0.500-0.350}  

<u>Thus, Kp = 0.81666</u>

7 0
3 years ago
Una disolución contiene 40% de ácido acético en masa. La densidad de la disolución es de 1.049 g/mL a 20°C. Calcule la masa de á
s344n2d4d5 [400]

Answer:

52.45g

Explanation:

The computation of the mass of pure acetic acid in 125mL of this solution is shown below:

The percentage of mass would be equivalent to the g of solute in each 100g of water

As we know that

density = mass ÷ volume

So,

Volume = mass ÷ density

V = 100g / 1.049 (g / ml)

V = 95.328 mL

Now In every 95,328 ml of C_2H_4O_2 there are 40g of C_2H_4O_2

i.e.

each 125ml of C_2H_4O_2 there are 52.45g

SO,

x = 40g. 125ml ÷ 95.328

x = 52.45g

4 0
3 years ago
What is the only thing that changes in a chemical reaction
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3 0
3 years ago
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