Answer:
The wavelength of the energy that needs to be absorbed = 52.36 nm
Explanation:
For this study;
Let consider the Rydgberg equation from Bohr's theory of atomic model:
i.e.

where
Z* = effective nuclear charge of atom = Z - σ = 6
n₁ = lower orbit = 3
n₂ = higher orbit = 4
= Rydyberg constant = 1.09 × 10⁷ m⁻¹
λ = wave length of the light absorbed
∴









Therefore, the wavelength of the energy that needs to be absorbed = 52.36 nm
Answer: Energy can be involved in disconnecting or connecting atoms to each other as the energy is used to break the bonds between the atoms ,so the reaction could proceed.
Explanation:<u> The statement can be well explained by the Planck's quantum theory , which states -:</u>
- In the form of small energy packets known as quanta of energy, energy is not released continuously, but discontinuously.
- The energy of each quantum is directly proportional to radiation frequency, i.e. E is directly proportional to v, where v is frequency E = hv, where h is the proportionality constant known as the constant of Planck.
- Any integer quanta will be the total energy of the radiation emitted or absorbed. Let the 'E' be the total radiation energy. So, when n is an integer, E'=nhv.
Hence, the given answer is based on the Planck's Quantum theory.
Answer:
m = 176.04 g .
Explanation:
Hello there!
In this case, according to the mole-mass relationships, which are based off the mass of one mole of any compound via the molar mass, it is possible to realize that the molar mass of carbon dioxide is 44.01 (12.01+16*2) g/mol, and therefore, the mass in grams of 4.00 moles of this compound are calculated as shown below:

Best regards!
Answer:
Upper H subscript 2 upper O plus upper H subscript 2 upper O double-headed arrow upper H subscript 3 upper O superscript plus, plus upper O upper H superscript minus.
Explanation:
The self-ionization of water is also known as the autoionization of water or autodissociation of water. It is an ionization reaction in pure water or in an aqueous solution, in which a water molecule, H2O, deprotonates that is, it loses one of its hydrogens to become a hydroxide ion, OH−. The hydrogen adds to another water molecule to form the oxonium ion. Water being an amphiprotic substance, can act as an acid by donating a proton to a base to form the hydroxide ion, or as a base by accepting a proton from an acid to form the hydronium ion (H3O+) as typified by its self ionization.
The autoionization of liquid water therefore produces OH− and H3O+ ions. The equilibrium constant for this reaction is called the ion-product constant of liquid water (Kw) and is defined as Kw=[H3O+][OH−].