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miss Akunina [59]
4 years ago
10

If a board with an area of 3m2 has a 12 N force exerted on it, what is the pressure on the board?

Physics
2 answers:
Cerrena [4.2K]4 years ago
4 0
4 N/cm^2 is the answer. the way you get this is the formula for pressure is P=F/A. So you would plug in the numbers which would make the equation P=12/3 which you know equals 4. The units for pressure is N/cm^2 or N/m^2

I hope this helps 
NemiM [27]4 years ago
3 0

Answer: 4 N/cm^2

Explanation:

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How are base units and derived units related?
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Answer:

SI derived units

Other quantities, called derived quantities, are defined in terms of the seven base quantities via a system of quantity equations. The SI derived units for these derived quantities are obtained from these equations and the seven SI base units.

Explanation:

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8 0
3 years ago
Suppose the Sun moved twice the distance from Earth. Describe immediate and future changes to our planet. Justify your reasoning
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3 years ago
Is Smoke Abiotic or Biotic?
nlexa [21]

Answer: Smoke is Abiotic because it is not a living thing.

Explanation: Hopefully this helps u.  Have a great rest of your day. I hope this is the right answer

6 0
3 years ago
When temperature and pressure are applied to sedimentary and igneous rock?
spin [16.1K]
Answer:

Igneous rock

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6 0
4 years ago
*A car is going through a dip in the road whose curvature approximates a circle of radius 150m. At what velocity will the occupa
Valentin [98]

Answer:

v= 14.85 m/s

Explanation:

  • When at the bottom of the dip, the only force that keeps the car in the circular trajectory, is the centripetal force.
  • This force is not a new force, is just the net force aiming to the center of the circle.
  • In this case, is just the difference between the normal force (always perpendicular to the surface, pointing upward) and the force that gravity exerts on the car (which is known as the weight), pointing downward.
  • So, we can write the following expression:

       F_{cent} = F_{n} - F_{g}  (1)

  • It can be showed that the centripetal force is related to the speed by the following expression:
  • F_{cent} = m*\frac{v^{2}}{r} (2)
  • The normal force, it is called the apparent weight, because it would be the weight as measured by a scale.
  • Replacing (2) in (1), and solving for Fn, we get:

       F_{n} = m*\frac{v^{2} }{r} + m*g (3)

  • Now, we need to find the value of v that makes Fn, exactly 15% more than the weight m*g, so we can write the following equation:

      F_{n} = 1.15*F_{g} = m*\frac{v^{2}}{r} +F_{g}  (4)

  • Replacing Fg by its value, simplifying, and solving for v, we get:

       v = \sqrt{0.15*g*r} = \sqrt{9.8 m/s2*0.15*150m} = 14.85 m/s (5)

3 0
3 years ago
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