The probability that a red ace is drawn first and then a black ace is mathematically given as
x=1/4
<h3>What is the probability that a red ace is drawn first and then a black ace?</h3>
Where
Sample mean=(x,y)\, x, y \in \{h,d,c,s\}
If we want a player to draw two cards of the same color from their deck, the following combinations of cards are appropriate choices:

Generally, 8 possible pairings above 16. This indicates that the likelihood of a player drawing two cards of the same color is 8/16, which is equivalent to a probability of half.
In conclusion, In a similar vein, the following pairs of cards illustrate the likelihood of obtaining a black ace after having drawn a red ace in the previous round:

Giving
x=4/16
x=1/4
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