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elena-14-01-66 [18.8K]
2 years ago
9

You are on a boat in a fog and know there are cliffs ahead of you somewhere, but you cannot see them. you use your fog horn to s

end out a blast of sound (assume the temperature of the air is 20 oc) and the time it takes for the sound to return to you is 20.0 s. how far away are the cliffs (in metric units)
Physics
1 answer:
ELEN [110]2 years ago
3 0

The distance of the cliff from where you are is determined as 3,430 m.

<h3>Distance of the cliff</h3>

Apply the formula for echo.

v = 2d/t

where;

  • v is speed of sound at 20 ⁰C = 343 m/s
  • d is distance = ?
  • t is time = 20 s

2d = vt

d = vt/2

d = (343 x 20)/2

d = 3430 m

Thus, the distance of the cliff from where you are is determined as 3,430 m.

Learn more about echo here: brainly.com/question/14090821

#SPJ1

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Answer:They will go off in opposite directions with the same force.

Explanation:

Newton's Third Law states that for every action, there is an equal but opposite reaction. If two people are standing on a scooter and push off each other (following the Law), it should come to the conclusion that they could go off in opposite with the same force.

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Dylan has two cubes of iron. The larger cube has twice the mass of the smaller cube. He measures the smaller cube. Its mass is 2
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Answer:

The volume of the larger cube is 5.08 g/cm³.

Explanation:

Given that,

Mass of smaller cube = 20 g

Density of smaller cube \rho= 7.87 g/cm^2

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The larger cube has twice the mass of the smaller cube.

M_{l}=2m_{s}

Density is same for both cubes because both cubes are same material.

The density is equal to the mass divided by the volume.

\rho=\dfrac{m}{V}

V=\dfrac{m}{\rho}

Where, V = volume

m = mass

\rho=density

We need to calculate the volume of smaller mass

The volume of smaller mass

V_{s}=\dfrac{m_{s}}{\rho_{s}}

V_{s}=\dfrac{20}{7.87}

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V_{l}=\dfrac{m_{l}}{\rho_{l}}

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3 years ago
A rotating flywheel has moment of inertia 18.0 kg⋅m^2 for an axis along the axle about which the wheel is rotating. Initially th
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Answer:

The rotational kinetic energy takes 0.430 seconds to become half its initial value.

Explanation:

By the Principle of Energy Conservation and the Work-Energy Theorem we know that flywheel slow down due to the action of non-conservative forces (i.e. friction), the energy losses are equal to the change in the rotational kinetic energy. That is:

\Delta E = K_{1}-K_{2} (1)

Where:

\Delta E - Energy losses, measured in joules.

K_{1}, K_{2} - Initial and final rotational kinetic energies, measured in joules.

By definition of rotational kinetic energy, we expand the equation above:

\Delta E = \frac{1}{2}\cdot I\cdot (\omega_{1}^{2}-\omega_{2}^{2}) (2)

Where:

I - Moment of inertia of the flywheel, measured in kilograms per square meter.

\omega_{1}, \omega_{2} - Initial and final angular speed, measured in radians per second.

If we know that K_{1} = 30\,J, K_{2} = 15\,J and I = 18\,kg\cdot m^{2}, then the initial angular speed is:

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\omega_{1}=\sqrt{\frac{2\cdot K_{1}}{I} }

\omega_{1} = \sqrt{\frac{2\cdot (30\,J)}{18\,kg\cdot m^{2}} }

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\omega_{2} \approx 1.291\,\frac{rad}{s}

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