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elena-14-01-66 [18.8K]
2 years ago
9

You are on a boat in a fog and know there are cliffs ahead of you somewhere, but you cannot see them. you use your fog horn to s

end out a blast of sound (assume the temperature of the air is 20 oc) and the time it takes for the sound to return to you is 20.0 s. how far away are the cliffs (in metric units)
Physics
1 answer:
ELEN [110]2 years ago
3 0

The distance of the cliff from where you are is determined as 3,430 m.

<h3>Distance of the cliff</h3>

Apply the formula for echo.

v = 2d/t

where;

  • v is speed of sound at 20 ⁰C = 343 m/s
  • d is distance = ?
  • t is time = 20 s

2d = vt

d = vt/2

d = (343 x 20)/2

d = 3430 m

Thus, the distance of the cliff from where you are is determined as 3,430 m.

Learn more about echo here: brainly.com/question/14090821

#SPJ1

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6 0
3 years ago
An object has a mass of 5.20g. The mass of the object in kg is​
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Answer:

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Explanation:

divide by 1000

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When you put a pot of water on the stove, the stove transfers thermal energy to the water. As the water gains large
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Answer:

It releases some of the energy into the atmosphere as hot steam.

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3 years ago
A 1300 kg car moving at 20 m/s and a 900 kg car moving at 15 m/s in precisely oppositedirections participate in a head-on crash.
miskamm [114]

Given

Car 1

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Procedure

As per the conservation of linear momentum, "The total momentum of the system before the collision must be equal to the total momentum after the collision". And this applies to the perfectly inelastic collision as well. Then the expression is,

\begin{gathered} m_1v_1+m_2v_2=(m_1+m_2)v \\ v=\frac{m_1v_1+m_2v_2}{m_1+m_2} \\ v=\frac{1300\operatorname{kg}\cdot20m/s-900\operatorname{kg}\cdot15m/s}{1300\operatorname{kg}+900\operatorname{kg}} \\ v=5.681m/s \end{gathered}

Thus, we can conclude that the speed and direction of the cars after the impact is 5.68 m/s towards the first car.

5 0
1 year ago
An object of mass 6.00 kg falls with an aceleration of 8.00 m/s2. The magnitude of air resitance must be ____ N
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7 0
3 years ago
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