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abruzzese [7]
3 years ago
13

PHYSICS I need help with number two!!!!

Physics
1 answer:
EleoNora [17]3 years ago
7 0

Answer:

mgh₁ + ½mv₁² = mgh₂ + ½mv₂²

Explanation:

Initial total energy = final total energy

PE₁ + KE₁ = PE₂ + KE₂

mgh₁ + ½mv₁² = mgh₂ + ½mv₂²

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What is the surface area for a rectangular prism with the height of 6 inches, width of 8 inches, and the length of 4 inches
podryga [215]

Answer:

208 is the surface area!

Explanation:

Hope this helps! ;-)

8 0
2 years ago
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Gamma radiation is composed of neutrons and protons.<br> A. True<br> B. False
konstantin123 [22]

Answer:

false

Explanation:

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3 years ago
the force of attraction between two objects is called gravity why do you think that an object like your note book pulls twords y
mr_godi [17]

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4 0
3 years ago
A farmhand pushes a 26-kg bale of hay 3.9 m across the floor of a barn. If she exerts a horizontal force of 88 N on the hay, how
Tamiku [17]

Answer:

W =  343.2 J

Explanation:

Given that,

Mass of bale of hay = 26 kg

Horizontal force exerted = 88 N

Distance moved, d = 3.9 m

Work done, W = Fd

Put all the values,

W = 88 N × 3.9 m

= 343.2 J

So, the work done is 343.2 J.  

7 0
3 years ago
A student wishes to record a 7.5-kilogram watermelon colliding with the ground. Calculate how far the watermelon must fall freel
algol [13]

Answer:

42.86m

Explanation:

The first thing we should keep in mind is that the watermelon moves with uniform acceleracion equal to gravity (9.81m / s ^ 2)

A body that moves with constant acceleration means that it moves in "a uniformly accelerated motion", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.

When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.

\frac {Vf^{2}-Vo^2}{2.g} =Y

where

Vf=29m/s= final speed

Vo= initial speed=0m/S

g=gravity=9.81m/s^2

Y= distance traveled(m)

solving

\frac {Vf^{2}-Vo^2}{2.g} =Y\\\frac {(29m/s)^{2}-(0m/s)^2}{2(9.8m/s^2)} =Y\\Y=42.86m\\

the distance traveled by watermelon is 42.86m

       

5 0
4 years ago
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