Question

choose the point-slope form of the equation below that represents the line that passes through the points (−3, 2) and (2, 1). y 3 = −5(x − 2) y − 2 = −5(x 3) y 3 = −one fifth(x − 2) y − 2 = −one fifth(x 3)

Answer 1

we know that

the point-slope form of the equation of the line is equal to

$y-y1=m(x-x1)$

so

Step $1$

Find the slope m

the slope is equal to

$m=\frac{(y2-y1)}{(x2-x1)}$

Let

$A(-3,2)\\ B(2,1)$

$m=\frac{(1-2)}{(2+3)}$

$m=-\frac{1}{5}$

Step $2$

with m and point A find the equation of the line

$y-2=-\frac{1}{5}(x+3)$

therefore

the answer is

the point-slope form of the equation is equal to

$y-2=-\frac{1}{5}(x+3)$

Answer 2

Hello,

y-2=(1-2)/(2+3)*(x+3)
==>y-2=-1/5 (x+3)

Answer D